Consider the following equation:
Cr2O72–(aq) + 3SO32– (aq)+ 8H+(aq) → A + B +4H2O(l)
The product A and B are respectively:
1. 2Cr2+; 3SO2
2. 2Cr+; S2O7 2-
3. 2Cr3+; 3SO4 2-
4. 2Cr3+; 3HSO42-
1. | 2 | 2. | 4 |
3. | 6 | 4. | 8 |
1. | c = 1; d = 2; f = 2 | 2. | c = 2; d = 1; f = 2 |
3. | c = 2; d = 2; f = 1 | 4. | c = 1; d = 1; f = 1 |
1. | 24 | 2. | 22 |
3. | 27 | 4. | 29 |
Permanganate(VII) ion, MnO4– in basic solution oxidizes iodide ion, I– to produce molecular iodine (I2) and manganese (IV) oxide (MnO2). The reaction is as follows:
aI–(aq) + bMnO4–(aq) + cH2O(l) → dI2(s) + eMnO2(s) + fOH–(aq)
The value of b, d and f are-
1. | b = 2; d = 3; f = 8 | 2. | b = 1; d = 3; f = 8 |
3. | b = 3; d = 8; f = 2 | 4. | b = 8; d = 3; f = 2 |