Match the bond line structures of hydrocarbons given in List I with the corresponding boiling points given in List II.
List-I (Compound) | List II (Boiling point in K) | ||
(a) | (i) | 300.9 | |
(b) | |
(ii) | 282.5 |
(c) | |
(iii) | 309.1 |
(d) | (iv) | 341.9 |
(a) | (b) | (c) | (d) | |
1. | (i) | (iv) | (iii) | (ii) |
2. | (iii) | (i) | (iv) | (ii) |
3. | (iii) | (iv) | (i) | (ii) |
4. | (iv) | (i) | (ii) | (iii) |
Match the hydrocarbons in Column I with the boiling points given in Column II.
A. n-Pentane | 1. 282.5 K |
B. Isopentane | 2. 309 K |
C. Neopentane | 3. 301 K |
Codes
Options: | A | B | C |
1. | 2 | 3 | 1 |
2. | 1 | 2 | 3 |
3. | 2 | 1 | 3 |
4. | 3 | 2 | 1 |
Consider the following compounds,
A. n-Butane
B. 2-Methylbutane
C. n-Pentane
D. 2, 2-Dimethylpropane
The correct decreasing order of their boiling points is-
1. A > B > C > D
2. B > C > D > A
3. C > B > D > A
4. D > C > B > A
Statement I : | The boiling point of three isomeric pentanes follows the order \(\small\text { n-Pentane }>\text { Isopentane }>\text { Neopentane }\) |
Statement II : | When branching increases, the molecule attains the shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point. |
Given below are two statements:
Assertion (A): | Among isomeric pentanes, 2,2-dimethylpropane has the highest boiling point. |
Reason (R): | Branching does not affect the boiling point. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | Both (A) and (R) are False. |
4. | (A) is True but (R) is False. |
Which of the following will not show geometrical isomerism?
1. | ![]() |
2. | ![]() |
3. | ![]() |
4. | ![]() |
1. | The first three members are gases. |
2. | All alkynes are odourless. |
3. | All alkynes are colourless. |
4. | Alkynes are lighter than water and immiscible with water. |
Which isomer of pent-2-ene will have a higher boiling point and why?
1. Cis - less polar than trans
2. Trans - more polar than cis
3. Cis - more intermolecular forces
4. Trans - more dipole-dipole interactions