Q. No.Match the bond line structures of hydrocarbons given in List I with the corresponding boiling points given in List II.
| List-I (Compound) | List II (Boiling point in K) | ||
| (a) |  |
(i) | 300.9 |
| (b) |  |
(ii) | 282.5 |
| (c) |  |
(iii) | 309.1 |
| (d) |  |
(iv) | 341.9 |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (i) | (iv) | (iii) | (ii) |
| 2. | (iii) | (i) | (iv) | (ii) |
| 3. | (iii) | (iv) | (i) | (ii) |
| 4. | (iv) | (i) | (ii) | (iii) |
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
81%
From NCERT
NEET - 2022
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Match the hydrocarbons in Column I with the boiling points given in Column II.
| A. n-Pentane | 1. 282.5 K |
| B. Isopentane | 2. 309 K |
| C. Neopentane | 3. 301 K |
Codes
| Options: | A | B | C |
| 1. | 2 | 3 | 1 |
| 2. | 1 | 2 | 3 |
| 3. | 2 | 1 | 3 |
| 4. | 3 | 2 | 1 |
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
87%
From NCERT
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Consider the following compounds,
A. n-Butane
B. 2-Methylbutane
C. n-Pentane
D. 2, 2-Dimethylpropane
The correct decreasing order of their boiling points is-
1. A > B > C > D
2. B > C > D > A
3. C > B > D > A
4. D > C > B > A
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
79%
From NCERT
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What is the correct order of boiling points for the following compounds, arranged from the highest to the lowest?
(a) Heptane
(b) Butane
(c) 2-Methylbutane
(d) 2-Methylpropane
(e) Hexane
Choose the correct option from the following:
(a) Heptane
(b) Butane
(c) 2-Methylbutane
(d) 2-Methylpropane
(e) Hexane
Choose the correct option from the following:
| 1. | (a) > (c) > (e) > (d) > (b) | 2. | (c) > (d) > (a) > (e) > (b) |
| 3. | (a) > (e) > (b) > (c) > (d) | 4. | (a) > (e) > (c) > (b) > (d) |
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
52%
From NCERT
NEET - 2022
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Given below are two statements :
In the light of the above statements, choose the most appropriate answer from the option given below:
1. Both Statement I and Statement II are incorrect.
2. Statement I is correct but Statement II is incorrect.
3. Statement I is incorrect but Statement II is correct.
4. Both Statement I and Statement II are correct.
| Statement I : | The boiling point of three isomeric pentanes follows the order \(\text { n-Pentane }>\text { Isopentane }>\text { Neopentane }\) |
| Statement II : | When branching increases, the molecule attains the shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point. |
1. Both Statement I and Statement II are incorrect.
2. Statement I is correct but Statement II is incorrect.
3. Statement I is incorrect but Statement II is correct.
4. Both Statement I and Statement II are correct.
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
72%
From NCERT
NEET - 2024
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Given below are two statements:
| Assertion (A): | Among isomeric pentanes, 2,2-dimethylpropane has the highest boiling point. |
| Reason (R): | Branching does not affect the boiling point. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | Both (A) and (R) are False. |
| 4. | (A) is True but (R) is False. |
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
81%
From NCERT
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Arrange the following compounds in increasing order of their solubilities in chloroform:
\(\mathrm{NaCl, CH_3 OH, cyclohexane, CH_3CN}\)
1. \(\mathrm{NaCl< CH_3CN<CH_3 OH<Cyclohexane}\)
2. \(\mathrm{CH_3 OH<CH_3CN<NaCl<Cyclohexane}\)
3. \(\mathrm{NaCl< CH_3 OH<CH_3CN<Cyclohexane}\)
4. \(\mathrm{Cyclohexane< CH_3CN<CH_3 OH<NaCl}\)
\(\mathrm{NaCl, CH_3 OH, cyclohexane, CH_3CN}\)
1. \(\mathrm{NaCl< CH_3CN<CH_3 OH<Cyclohexane}\)
2. \(\mathrm{CH_3 OH<CH_3CN<NaCl<Cyclohexane}\)
3. \(\mathrm{NaCl< CH_3 OH<CH_3CN<Cyclohexane}\)
4. \(\mathrm{Cyclohexane< CH_3CN<CH_3 OH<NaCl}\)
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
From NCERT
NEET - 2024
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Subtopic: Aliphatic Hydrocarbon- Physical Properties |
84%
From NCERT
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Mark the Incorrect statement among the following about the alkynes.
1. The first three members are gases.
2. All alkynes are odourless.
3. All alkynes are colourless.
4. They are lighter than water and immiscible with water.
1. The first three members are gases.
2. All alkynes are odourless.
3. All alkynes are colourless.
4. They are lighter than water and immiscible with water.
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
From NCERT
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Among the two isomers given above, the reason behind higher boiling point of one isomer as compared to the order is :
1. Cis - less polar than trans
2. Trans - more polar than cis
3. Cis - more intermolecular forces
4. Trans - more dipole-dipole interactions
Subtopic: Aliphatic Hydrocarbon- Physical Properties |
60%
From NCERT
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