Match the laws given in Column I with expressions given in Column II.

Column I Column II
A. Raoult’s law 1. π = CRT
B. Osmotic pressure  2. ΔTf=Kfm
C. Elevation of boiling point 3. p=x1p10 +x2p20
D. Depression in freezing point 4. ΔTb=Kbm

Codes

A B C D
1. 2 3 4 1
2. 1 2 3 4
3. 1 4 3 2
4. 3 1 4 2
Subtopic:  Elevation of Boiling Point | Depression of Freezing Point |
 94%
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The freezing point of depression constant (Kf ) of benzene is 5.12 K kg mol–1. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is:
(rounded off up to two decimal places)
1. 0.80 K
2. 0.40 K
3. 0.60 K
4. 0.20 K

Subtopic:  Depression of Freezing Point |
 87%
From NCERT
NEET - 2020
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Select the correct option based on statements below:

Assertion (A): When NaCl is added to water a depression in freezing point is observed.
Reason (R): The lowering of vapour pressure of a solution causes depression in the freezing point.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.

Subtopic:  Depression of Freezing Point |
 72%
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45 g of ethylene glycol (C2H6O2) is mixed with 600 g of water. The freezing point of the solution is:

1. 268.15 K
2. 270.95 K
3. 272.75 K
4. 267.15 K

Subtopic:  Depression of Freezing Point |
 65%
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When 5 g of non-volatile non-electrolyte solute is dissolved in 100 g of a certain solvent, the freezing point of the solvent decreases by 0.25 K. The molar mass of the solute is:
\([\text{K}_f \) of the given solvent \( =1.2 \mathrm{K ~kg}~ \mathrm{mol}^{-1}] \)
1. \(242.8 \mathrm{~g} \mathrm{~mol}^{-1}\) 2. \(238.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
3. \(241.8 \mathrm{~g} \mathrm{~mol}^{-1}\) 4. \(240.0 \mathrm{~g} \mathrm{~mol}^{-1}\)
Subtopic:  Depression of Freezing Point |
 81%
From NCERT
NEET - 2024
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The incorrect statement among the following is:

1. Units of atmospheric pressure and osmotic pressure are the same.
2. In reverse osmosis, solvent molecules move through a semipermeable membrane from a region of lower concentration of solute to a region of higher concentration.
3. The value of molal depression constant depends on nature of solvent.
4. Relative lowering of vapour pressure, is a dimensionless quantity.

Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point | Depression of Freezing Point | Osmosis & Osmotic Pressure |
 67%
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The mass of ascorbic acid (Vitamin C, C6H8O6) to be dissolved in 75 g of acetic acid
to lower its melting point by 1.5°C, is:
(Kf = 3.9 K kg mol−1)

1. 5.19 g
2. 5.08  g
3. 5.65 g
4. 5.48 g
 
Subtopic:  Depression of Freezing Point |
 71%
From NCERT
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0.6 mL of acetic acid (CH3COOH), having density 1.06 g mL–1, is dissolved in 1 litre of water. The depression in freezing point observed for this strength of acid was 0.0205°C. The value of van’t Hoff factor and the dissociation constant of acid are respectively:

1. 1.041; 1.86 × 10–5
2. 2.073; 1.86 × 10–5
3. 0.091; 1.76 × 10–5
4. 1.041; 1.76 × 10–5

Subtopic:  Depression of Freezing Point | Van’t Hoff Factor |
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In comparison to a 0.01 M solution of glucose, the depression in the freezing point of a 0.01 M MgCl2 solution will be:

1. Same 2. About twice
3. About three times 4. About six times
Subtopic:  Depression of Freezing Point |
 82%
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A 5 % solution (by mass) of cane sugar in water has freezing point of 271 K. Freezing point of 5 % glucose in water would be: (freezing point of pure water is 273.15 K)

1. 279.24 K

2. –269.06 K

3. 275.42 oC

4. 269.06 K

Subtopic:  Depression of Freezing Point |
 55%
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