Q. No.
Match the terms given in Column I with expressions given in Column II.
| Column I (Term) | Column II (Expression) |
| A. Mass percentage | 1. \(\text{Number of moles of the solute component} \over \text{Volume of solution in litres}\) |
| B. Volume percentage | 2. \(\text{Number of moles of the solute component} \over \text{Mass of solvent in kilograms}\) |
| C. Molarity | 3. \(\small{\text{Volume of the solute component in solution} \over \text{Total volume of solution}} \times 100\) |
| D. Molality | 4. \(\small{\text{Mass of the solute component in solution} \over \text{Total Mass of solution}} \times 100\) |
Codes:
| A | B | C | D | |
| 1. | 2 | 3 | 4 | 1 |
| 2. | 1 | 2 | 3 | 4 |
| 3. | 1 | 4 | 3 | 2 |
| 4. | 4 | 3 | 1 | 2 |
Match the items given in Column I with the type of solutions given in Column II.
| Column I | Column II |
| A. Soda water | 1. A solution of gas in solid |
| B. Sugar solution | 2. A solution of gas in liquid |
| C. German silver | 3. A solution of solid in liquid |
| D. Hydrogen gas in palladium | 4. A solution of solid in solid |
Codes:
| A | B | C | D | |
| 1. | 2 | 1 | 4 | 3 |
| 2. | 1 | 2 | 3 | 4 |
| 3. | 2 | 3 | 4 | 1 |
| 4. | 4 | 1 | 3 | 2 |
The mole fraction of glucose (C6H12O6) in an aqueous binary solution is 0.1. The mass percentage of water in it to the nearest integer is:
| 1. | 44% | 2. | 49 % |
| 3. | 47 % | 4. | 41 % |
| 1. | 212000 ppm | 2. | 212 ppm |
| 3. | 2120 ppm | 4. | 21.2 ppm |
The mole fraction of ethylene glycol (C2H6O2) in a solution containing 20% of C2H6O2 by mass is:
1. 0.932
2. 0.0672
3. 0.832
4. 0.732
The molarity of a solution containing 5 g of NaOH in 450 mL solution is:
1. 0.188 mol dm–3
2. 0.478 mol dm–3
3. 0.378 mol dm–3
4. 0.278 mol dm–3
4 L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molarity of the resultant solution is:
| 1. | 0.004 M | 2. | 0.008 M |
| 3. | 0.012 M | 4. | 0.016 M |
The molality of 2.5 g of ethanoic acid (CH3COOH) in 75 g of benzene is:
1. 0.656 mol kg–1
2. 0.616 mol kg–1
3. 0.556 mol kg–1
4. 0.456 mol kg–1
The molarity of 30 g Co(NO3)2. 6H2O in 4.3 L of solution is:
1. 0.053 M
2. 0.043 M
3. 0.023 M
4. 0.063 M
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