Q. No.
The graph representing Henry's law is given below:
The value of the slope will be:
| 1. | \(4\times10^{-4}~\mathrm{torr}\) | 2. | \(5\times10^{-4}~\mathrm{torr}\) |
| 3. | \(4\times10^{4}~\mathrm{torr}\) | 4. | \(5\times10^{4}~\mathrm{torr}\) |
The type of molecular interactions in a solution of alcohol and water is:
| 1. | Electrostatic interaction | 2. | London dispersion forces |
| 3. | Hydrogen bonding | 4. | Ion-dipole interaction |
A solution of glucose (M.W. = 180 g mol–1) in water is 10 % w/w. The mole fraction of each component in the solution is:
| 1. | Mole fraction of glucose - 0.44; mole fraction of water - 0.56 |
| 2. | Mole fraction of glucose - 0.056; mole fraction of water - 0.944 |
| 3. | Mole fraction of glucose - 0.011; mole fraction of water - 0.99 |
| 4. | Mole fraction of glucose - 0.36; mole fraction of water - 0.64 |
| Type of solution | Example | ||
| a. | Solid in gas | i. | Aerated water |
| b. | Gas in liquid | ii. | Smoke |
| c. | Liquid in solid | iii. | Solution of hydrogen in palladium |
| d. | Gas in solid | iv. | Amalgams |
| a | b | c | d | |
| 1. | i | iii | iv | ii |
| 2. | ii | i | iv | iii |
| 3. | iii | i | iv | ii |
| 4. | iv | i | ii | iii |
Which law is applied when deep-sea divers use a breathing mixture of oxygen and less soluble helium to minimise the painful effects caused by the increased dissolution of gases in blood at high pressure?
| 1. | Raoult's law | 2. | Henry's law |
| 3. | Ideal gas Equation | 4. | All of the above |
The solubility of gases in liquids generally decreases as temperature increases.
The primary reason for this behavior is:
| 1. | Dissolution of a gas in a liquid is an endothermic process. |
| 2. | Dissolution of a gas in a liquid is an exothermic process. |
| 3. | Gases are highly compressible. |
| 4. |
All of the above statements are correct. |
The solubility of \(H_2S\) in water at STP is 0.195 m. The value of Henry's constant is:
| 1. | 274 atm | 2. | 285 atm |
| 3. | 295 atm | 4. | 278 atm |
Henry’s law constant for the solution of methane in benzene at 298 K is 4.27 × 105 mm Hg. The mole fraction of methane in benzene at 298 K under 760 mm Hg will be:
1. 1.85 × 10–5
2. 192 × 10–4
3. 178 × 10–5
4. 18.7 × 10–5
The amount of benzoic acid (C6H5COOH) required for preparing 250 mL of 0.15 M solution in methanol is:
| 1. | 4.57 g | 2. | 3.57 g |
| 3. | 1.57 g | 4. | 12.57 g |
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