A block of mass \(m\) is placed between two springs connected to the ends of a railroad car. The surface supporting the block is horizontal, and the spring are initially relaxed. The car is given an acceleration \(a\) and the mass \(m\) finally comes to equilibrium within the car. Let \(x\) be the compression (or extension) in the two springs. Assume friction to be negligible. Then:
                          
 
1. \(k_1x-k_2x=ma \)
2. \(\frac{k_1k_2}{k_1+k_2}x=ma \)
3. \(k_1x+k_2x=ma \)
4. \(\frac{k_1k_2}{k_1-k_2}=ma \)
Subtopic:  Spring Force |
 57%
From NCERT
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A massless and inextensible string connects two blocks \(\mathrm{A}\) and \(\mathrm{B}\) of masses \(3m\) and \(m,\) respectively. The whole system is suspended by a massless spring, as shown in the figure. The magnitudes of acceleration of \(\mathrm{A}\) and \(\mathrm{B}\) immediately after the string is cut, are respectively:
         

1. \(\dfrac{g}{3},g\) 2. \(g,g\)
3. \(\dfrac{g}{3},\dfrac{g}{3}\) 4. \(g,\dfrac{g}{3}\)

Subtopic:  Spring Force |
 70%
From NCERT
NEET - 2017
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