A remote sensing satellite of earth revolves in a circular orbit at a height of \(0.25 \times10^6~\text{m}\) above the surface of the earth. If Earth’s radius is \(6.38\times10^6~\text{m}\) and \(g=9.8~\text{ms}^{-2}\), then the orbital speed of the satellite is:
1. \(7.76~\text{kms}^{-1}\)
2. \(8.56~\text{kms}^{-1}\)
3. \(9.13~\text{kms}^{-1}\)
4. \(6.67~\text{kms}^{-1}\)

Subtopic:  Orbital velocity |
 51%
From NCERT
NEET - 2015
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A satellite \(S\) is moving in an elliptical orbit around the earth. If the mass of the satellite is very small as compared to the mass of the earth, then:

1. The angular momentum of \(S\) about the centre of the earth changes in direction, but its magnitude remains constant.
2. The total mechanical energy of \(S\) varies periodically with time.
3. The linear momentum of \(S\) remains constant in magnitude.
4. The acceleration of \(S\) is always directed towards the centre of the earth.
Subtopic:  Orbital velocity |
 57%
From NCERT
NEET - 2015
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If \(v_e\) is the escape velocity and \(v_0\) is the orbital velocity of a satellite for orbit close to the earth's surface, then these  are related by:
1. \(v_o=v_e\) 2. \(v_e=\sqrt{2v_o}\)
3. \(v_e=\sqrt{2}~v_o\) 4. \(v_o=\sqrt{2}~v_e\)
Subtopic:  Orbital velocity |
 76%
From NCERT
AIPMT - 2012
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