A force of \(20\) N acts on a particle along a direction, making an angle of \(60^\circ\) with the vertical. The component of the force along the vertical direction will be:

1. \(2\) N 2. \(5\) N
3. \(10\) N 4. \(20\) N
Subtopic:  Resolution of Vectors |
 89%
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If \(\overrightarrow {A}= 2\hat i + 4\hat j- 5\hat k,\) then the direction cosines of the vector are:

(direction cosines (or directional cosines) of a vector are the cosines of the angles between the vector and the three \(+\)ve coordinate axes.)
1. \(\frac{2}{\sqrt{45}}, \frac{4}{\sqrt{45}}~\text{and}~\frac{-5}{\sqrt{45}}\)
2. \(\frac{1}{\sqrt{45}}, \frac{2}{\sqrt{45}}~\text{and}~\frac{3}{\sqrt{45}}\)
3. \(\frac{4}{\sqrt{45}}, 0~\text{and}~\frac{4}{\sqrt{45}}\)
4. \(\frac{3}{\sqrt{45}}, \frac{2}{\sqrt{45}}~\text{and}~\frac{5}{\sqrt{45}}\)

Subtopic:  Resolution of Vectors |
 88%
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\(\overrightarrow {A}\) is a vector with magnitude \(A\), then the unit vector \(\hat{A}\) in the direction of \(\overrightarrow {A}\) is:
1. \(A\overrightarrow A\)
2. \(\overrightarrow A \cdot\overrightarrow A\)
3. \(\overrightarrow A \times \overrightarrow A\)
4. \(\frac{\overrightarrow A}{A}\)
Subtopic:  Resolution of Vectors |
 80%
From NCERT
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A force \(F\) applied at a \(30^\circ\) angle to the \(x \)-axis has the following \(X\) and \(Y\) components:
1. \(\frac{F}{\sqrt{2}}, F\)
2. \(\frac{F}{2}, \frac{\sqrt{3}}{2}F\)
3. \(\frac{\sqrt{3}}{2}F, \frac{1}{2}F\)
4. \(F , \frac{F}{\sqrt{2}}\)

Subtopic:  Resolution of Vectors |
 79%
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A child pulls a box with a force of \(200~\text{N}\) at an angle of \(60^{\circ}\) above the horizontal. Then the horizontal and vertical components of the force will be:
              

1. \(100~\text{N}, ~175~\text{N}\)
2. \(86.6~\text{N}, ~100~\text{N}\)
3. \(100~\text{N}, ~86.6~\text{N}\)
4. \(100~\text{N}, ~0~\text{N}\)

Subtopic:  Resolution of Vectors |
 69%
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If \(\overrightarrow A= 3\hat i + 4\hat j\) and \(\overrightarrow B = 7\hat i + 24\hat k\), then the vector having the same magnitude as that of \(\overrightarrow {B}\) and parallel to \(\overrightarrow {A}\) is:
1. \(15\hat i + 20\hat j\)
2. \(\frac{7}{5}\hat i + \frac{24}{5}\hat j\)
3. \(20\hat i + 15\hat j\)
4. \(15\hat i + 20\hat k\)

Subtopic:  Resolution of Vectors |
 59%
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A force is \(60^{\circ}\) inclined to the horizontal. If its rectangular component in the horizontal direction is \(50\) N, then the magnitude of the force in the vertical direction is:

1. \(25\) N 2. \(75\) N
3. \(87\) N 4. \(100\) N
Subtopic:  Resolution of Vectors |
 60%
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Figure shows the orientation of two vectors \(u\) and \(v\) in the XY plane.
 If \(u = a\hat i + b\hat j\) and \(v = p\hat i + q\hat j\)


Which of the following is correct?

1. \(a\) and \(p\) are positive while \(b\) and \(q\) are negative
2. \(a, p,\) and \(b\) are positive while \(q\) is negative
3. \(a,q,\) and \(b\) are positive while \(p\) is negative
4. \(a, b, p,\) and \(q\) are all positive
Subtopic:  Resolution of Vectors |
 57%
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If a unit vector \(\hat j\) is rotated through an angle of \(45^{\circ}\) anticlockwise, then the new vector will be:
1. \(\sqrt{2}\hat i + \sqrt{2}\hat j\)
2. \(\hat i + \hat j\)
3. \(\frac{1}{\sqrt{2}}\hat i + \frac{1}{\sqrt{2}}\hat j\)
4. \(-\frac{1}{\sqrt{2}}\hat i + \frac{1}{\sqrt{2}}\hat j\)

Subtopic:  Resolution of Vectors |
 56%
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A certain vector in the xy-plane has an x-component of \(4\) m and a y-component of \(10\) m. It is then rotated in the xy-plane so that its x-component is doubled. Then, its new y-component will be: (approximately)
1. \(20\) m
2. \(7.2\) m
3. \(5.0\) m
4. \(4.5\) m
Subtopic:  Resolution of Vectors |
 52%
From NCERT
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