In a vernier callipers, \((N+1)\) divisions of the vernier scale coincide with \(N\) divisions of the main scale. If \(1\) \(\text{MSD}\) represents \(0.1~\text{mm}\), the vernier constant (in \(\text{cm}\)) is:
1. \(\dfrac{1}{100(N+1)} \) 2. \(100N\)
3. \(10(N+1) \) 4. \(\dfrac{1}{10 N}\)
Subtopic:  Measurement & Measuring Devices |
 71%
From NCERT
NEET - 2024
Please attempt this question first.
Hints
Please attempt this question first.

A vernier calipers has \(1~\text{mm}\) marks on the main scale. It has \(20\) equal divisions on the vernier scale which match with \(16\) main scale divisions. The least count of this vernier calipers is:
1. \(0.02~\text{mm}\) 
2. \(0.05~\text{mm}\)
3. \(0.10~\text{mm}\)
4. \(0.20~\text{mm}\)
Subtopic:  Measurement & Measuring Devices |
 65%
From NCERT
NEET - 2024
Please attempt this question first.
Hints
Please attempt this question first.

The pitch of an error-free screw gauge is \(1~\text{mm}\) and there are \(100\) divisions on the circular scale. While measuring the diameter of a thick wire, the pitch scale reads \(1~\text{mm}\) and \(63^\text{rd}\) division on the circular scale coincides with the reference line. The diameter of the wire is:
1. \(1.63 ~\text{cm}\)
2. \(0.163 ~\text{cm}\)
3. \(0.163~\text m\)
4. \(1.63 ~\text m\)
Subtopic:  Measurement & Measuring Devices |
 83%
From NCERT
NEET - 2024
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

The diameter of a spherical bob, when measured with vernier callipers yielded the values: \(3.33\) cm, \(3.32\) cm, \(3.34\) cm, \(3.33\) cm and \(3.32\) cm. The mean diameter to appropriate significant figures is:
1. \(3.328\) cm
2. \(3.3\) cm
3. \(3.33\) cm
4. \(3.32\) cm
Subtopic:  Measurement & Measuring Devices |
 56%
From NCERT
NEET - 2023
Please attempt this question first.
Hints
Please attempt this question first.

When the circular scale of a screw gauge completes \(2\) rotations, it covers \(1\) mm over the pitch scale. The total number of circular scale divisions is \(50\). The least count of the screw gauge in metres is:
1. \(10^{-4}\)
2. \(10^{-5}\)
3. \(10^{-2}\)
4. \(10^{-3}\)

Subtopic:  Measurement & Measuring Devices |
 54%
From NCERT
NEET - 2022
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

A screw gauge has the least count of \(0.01~\text{mm}\) and there are \(50\) divisions in its circular scale. The pitch of the screw gauge is:
1. \(0.25\) mm
2. \(0.5\) mm
3. \(1.0\) mm
4. \(0.01\) mm

Subtopic:  Measurement & Measuring Devices |
 84%
From NCERT
NEET - 2020
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

The angle of \(1'\) (minute of an arc) in radian is nearly equal to:
1. \(2.91 \times 10^{-4} ~\mathrm{rad} \)
2. \(4.85 \times 10^{-4} ~\mathrm{rad} \)
3. \(4.80 \times 10^{-6} ~\mathrm{rad} \)
4. \(1.75 \times 10^{-2} ~\mathrm{rad}\)

Subtopic:  Measurement & Measuring Devices |
 53%
From NCERT
NEET - 2020
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

The main scale of a vernier calliper has \(n\) divisions/cm. \(n\) divisions of the vernier scale coincide with \((n-1)\) divisions of the main scale. The least count of the vernier calliper is:
1. \(\dfrac{1}{(n+1)(n-1)}\) cm
2. \(\dfrac{1}{n}\) cm
3. \(\dfrac{1}{n^{2}}\) cm
4. \(\dfrac{1}{(n)(n+1)}\) cm

Subtopic:  Measurement & Measuring Devices |
 50%
From NCERT
NEET - 2019
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch