Q. No.An element belongs to group 15 and 3rd period of the periodic table. Its electronic configuration would be:
1. \(\mathrm{1 s^2 2 s^2 2 p^4}
\)
2. \(\mathrm{1 s^2 2 s^2 2 p^3}
\)
3. \(\mathrm{1 s^2 2 s^2 2 p^6 3 s^2 3 p^2}
\)
4. \(\mathrm{1 s^2 2 s^2 2 p^6 3 s^2 3 p^3}\)
Oxidation of nitrogen among the following reactions is indicated by -
1. \(\mathrm{N}_2 \rightarrow 2 \mathrm{NH}_3
\)
2. \(\mathrm{N}_2 \mathrm{O}_4 \rightarrow 2 \mathrm{NO}_2
\)
3. \(\mathrm{NO}_3{ }^{-} \rightarrow \mathrm{N}_2 \mathrm{O}_5
\)
4. \(\mathrm{NO}_2^{-} \rightarrow \mathrm{NO}_3^{-}\)
The bonding present in nitrogen molecules is:
1. \(p\pi-p\pi\)
2. \(p\pi-d\pi\)
3. \(d\pi-d\pi\)
4. Only sigma bond
Nitrogen exists as a diatomic molecule and phosphorus as P4 because on moving
| 1. | up a group, the tendency to form pπ−pπ bonds decreases. |
| 2. | down a group, the tendency to form pπ−pπ bonds decreases. |
| 3. | down a group, the tendency to form dπ−dπ bonds decreases. |
| 4. | up a group, the tendency to form dπ−dπ bonds decreases. |
Which of the following statements is true?
| 1. | NH3 is less soluble than PH3 in water |
| 2. | NH3 is a stronger base and stronger reducing agent than PH3 |
| 3. | NH3 has a higher boiling point than PH3 and has a lower melting point than PH3 |
| 4. | PH3 is a stronger reducing agent than NH3 and it has lower melting critical temperature than NH3 |
Which of the following is in the correct sequence?
[For the correct order mark (T) and for the incorrect order mark (F)]:
| (a) | Lewis acidity order | |
| (b) | Melting point | |
| (c) | Boiling point | |
| (d) | Dipole moment order |
| (a) | (b) | (c) | (d) | |
| 1. | F | T | F | T |
| 2. | T | F | T | F |
| 3. | F | F | T | T |
| 4. | F | F | T | F |
The false statement regarding hydrides from the 15th group is:
| 1. | NH3 > PH3 > AsH3 > SbH3 > BiH3 | Thermal stability |
| 2. | N-H > P-H > As-H > Sb-H > Bi-H | E-H bond dissociation enthalpy |
| 3. | NH3 > PH3 > AsH3 > SbH3 > BiH3 | Reducing character |
| 4. | NH3 > PH3 > AsH3 > SbH3 > BiH3 | Basicity |
In the nitrogen family, the H-M-H bond angle in the hybrides MH3 gradually becomes closer to 90o if we move from N to Sb. This shows that gradually
| 1. | The basic strength of hybrides increases. |
| 2. | Pure p-orbitals (almost) are used for M-H bonding. |
| 3. | The bond energies of the M-H bond increase. |
| 4. | The bond pairs of electrons become nearer to the central atom. |
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