Which reagent transforms nitromethane into methylamine?
1. Zn/HCl
2. Zn/NaOH
3. Zn/C2H5OH
4. Ni/H2
The reagent that is used to convert acetamide into methyl amine is:
1. NaOH-Br2
2. Soda lime
3. Hot conc. H2SO4
4. PCl5
1. CH3NH2
2. NCCH2NH2
3. (CH3)2NH
4. C6H5NHCH3
The final product C in the below mentioned reaction is:
\(\xrightarrow[]{Ac_2O}\ A\ \xrightarrow[CH_3COOH]{Br_2}\ B\ \xrightarrow[H^+]{H_2O}\ C\)
\(\xrightarrow[]{Ac_2O}\ A\ \xrightarrow[CH_3COOH]{Br_2}\ B\ \xrightarrow[H^+]{H_2O}\ C\)
1. | 2. | ||
3. | 4. |
Match the reactions given in Column I with the statements given in Column II.
Column I | Column II |
A. Ammonolysis | 1. Amine with a lesser number of carbon atoms |
B. Gabriel phthalimide synthesis | 2. Detection test for primary amines. |
C. Hofmann bromamide reaction | 3. Reaction of phthalimide with KOH and R—X |
D. Carbylamine reaction | 4. Reaction of alkyl halides with NH3 |
Codes:
A | B | C | D | |
1. | 2 | 3 | 4 | 1 |
2. | 3 | 1 | 4 | 2 |
3. | 1 | 4 | 3 | 2 |
4. | 4 | 3 | 1 | 2 |
1. | 2. | ||
3. | 4. |
Based on the statements given, which option is correct?
Assertion (A): | Nitration of aniline at a low temperature gives 47% m-nitroaniline. |
Reason (R): | In acidic medium, group is converted into group which is m-directing. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
Benzene diazonium chloride on reaction with aniline in the presence of dilute hydrochloric acid gives:
1. | 2. | ||
3. | 4. |