To study whether a gene exhibits multiple allelism or not, one must study:
1. | An individual | 2. | A population |
3. | A species | 4. | With concentration! |
A graphical representation to calculate the probability of all possible genotypes of offspring in a genetic cross is called as:
1. | Forked line diagram | 2. | Punnett square |
3. | Pedigree chart | 4. | Idiogram |
‘When two pairs of traits are combined in a hybrid, segregation of one pair of characters is independent of the other pair of characters’. This is the statement of:
1. Law of Dominance
2. Law of segregation
3. Law of Independent Assortment
4. Law of Linkage
Mendelian disorders are mainly determined by:
1. | Alteration or mutation in a single gene. |
2. | Chromosomal gross structural changes. |
3. | Recombination between linked genes. |
4. | Jumping genes |
In 1900, Mendel’s work was rediscovered by:
1. | Khorana, Nirenberg and Mathei |
2. | de Vries, Correns and von Tschermak |
3. | Avery, McCleod and McCarty |
4. | Watson, Crick and Wilkins |
What can be the blood groups of progeny whose father and mother are of AB and O blood groups, respectively?
1. | A and B only | 2. | AB only |
3. | All except O | 4. | A, B, AB, and O |
In the case of starch synthesis in pea seeds [controlled by the B gene], BB homozygotes produce large and round starch grains; bb homozygotes produce smaller and wrinkled starch grains and heterozygotes produce round seeds of intermediate size. What can be inferred from this observation?
1. | The gene B mutates at a faster rate |
2. | The gene B is easily influenced by the environment |
3. | Dominance is not an autonomous feature of a gene or the product that it has information for. |
4. | Some genes do not follow the law of segregation. |
In birds, the mechanism of sex determination is:
1. | XX – XY; male heterogamety |
2. | ZZ – ZW; female heterogamety |
3. | XX – XO; male heterogamety |
4. | ZZ – ZW; male heterogamety |
When the two genes in a dihybrid cross are situated on the same chromosome:
1. | The proportion of parental gene combinations was much higher than the non-parental type. |
2. | The proportion of parental gene combinations was much lesser than the non-parental type. |
3. | The proportion of parental gene combinations was equal to the non-parental type. |
4. | Only recombinants are formed. |
What is the ratio of a typical monohybrid test cross?
1. | 2 : 1 | 2. | 3 : 1 |
3. | 1: 2 : 1 | 4. | 1 : 1 |