One mole of oxygen gas at STP is equal to:
| (a) | 6 .022× 1023 molecules of oxygen |
| (b) | 6.022 × 1023 atoms of oxygen |
| (c) | 16 g of oxygen molecule |
| (d) | 32 g of oxygen |
Choose the correct answer from the option given below:
1. (a) and (b)Sulphuric acid reacts with sodium hydroxide according to the reaction:
When 1L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained are respectively-
| 1. | 0.1 M, 7.10 g | 2. | 7.10 g, 0.025 M |
| 3. | 0.025 M, 3.55 g | 4. | 3.55 g, 0.25 M |
| List-I | List-II | ||
| a. | Micro | i. | m |
| b. | Mega | ii. | m |
| c. | Giga | iii. | m |
| d. | Femto | iv. | m |
| a | b | c | d | |
| 1. | i | iv | iii | ii |
| 2. | iii | iv | ii | i |
| 3. | ii | iii | iv | i |
| 4. | i | iii | iv | ii |
When 50.0 kg of nitrogen gas (N2) and 10.0 kg of hydrogen gas (H2) are combined, what is the quantity of ammonia gas (NH3) produced?
1. 33.0 ×103 mol
2. 56.1×103 g
3. 6.5 ×103 g
4. None of the above
A solution is prepared by adding 2 g of substance A to 18 g of water. The mass percent of the solute is:
1. 20%
2. 10%
3. 15%
4. 18%
Find the mass of NaNO₃ required to prepare 50 mL of aqueous solution containing 70.0 mg Na⁺ per mL.
(Round off to the nearest integer.
Given: Na = 23, N = 14, O = 16)
| 1. | 13 g | 2. | 26 g |
| 3. | 18 g | 4. | 22 g |
Find the mass of CaCO₃ required to completely react with 25 mL of 0.75 M HCl according to the reaction:
CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)
1. 0.36 g
2. 0.09 g
3. 0.96 g
4. 0.66 g
How many significant figures are present in the following numbers?
| (I) | 161 cm |
| (II) | 0.0161 |
| (III) | 1.61 |
1. 3, 3, 3
2. 3, 4, 3
3. 3, 2, 3
4. 3, 4, 4
An aqueous solution contains 18 g of urea in 1500 cm³ of solution.
If the density of the solution is 1.052 g cm⁻³ and the molar mass of urea is 60 g mol⁻¹,
calculate the molality of the solution.
1. 0.2
2. 0.192
3. 0.064
4. 1.2
Percentage of C, H & N in a compound is given as follows:
C=40%; H=13.33%; N=46.67%
The empirical formula of the compound will be:
1.
2.
3.
4.