What is the alteration in the oxidation state of carbon in the given reaction?
\(\mathrm{{CH_4}_{(g)} + 4{Cl_2}_{(g)} \rightarrow {CCl_4}_{(l)} + 4 HCl_{(g)}}\)
| 1. | 0 to +4 | 2. | –4 to +4 |
| 3. | 0 to –4 | 4. | +4 to +4 |
Which of the following does not represent a redox reaction?
1. Cr2O72- + 2OH- CrO42- + H2O
2. SO42- + 2I- + 2H+ I2 + H2S + H2O
3. Ca + 2H2O → Ca(OH)2 + H2
4. PCl5 PCl3 + Cl2
An atom is said to be in the +6 oxidation state when it has effectively lost six electrons.
Which of the following species contains such an atom?
1. MnO4-
2. Cr(CN)63-
3. NiF62-
4. CrO2Cl2
The oxidation number of the atom (in bold) in the following species is given. Identify, which one is incorrectly related?
1. \(\mathbf{Cu}_{2} O\) is \(- 1\)
2. \(\mathbf{Cl} O_{3}^{-}\) is \(+ 5\)
3. \(K_{2} \mathbf{Cr}_{2} O_{7}\) is \(+ 6\)
4. \(H \mathbf{Au} Cl_{4}\) is \(+ 3\)
The oxidation number and covalency of sulphur in the sulphur molecule (S8) are respectively:
1. 0, and 2
2. +6, and 8
3. 0, and 8
4. +6, and 2
Among the following the correct order of acidity is-
1. HClO < HClO2< HClO3< HClO4
2. HClO2< HClO < HClO3< HClO4
3. HClO4< HClO2< HClO < HClO3
4. HClO3< HClO4< HClO2< HClO
In the given reaction, what is the name of the species that bleaches the substances due to its oxidising action?
Cl2(g) + 2OH-(aq) → ClO-(aq) + Cl-(aq) + H2O(l)
1. ClO-
2. Cl2
3. Cl-
4. Both ClO- and Cl-
| 1. | Due to manganese being in its highest oxidation state in MnO₄²⁻. |
| 2. | Due to manganese being in its highest oxidation state in MnO₄⁻ |
| 3. | Because the disproportionation reaction of MnO₄²⁻ is endothermic. |
| 4. | Because the disproportionation reaction of MnO₄²⁻ is exothermic. |
The oxidation state of P in is-
| 1. | +3 | 2. | +4 |
| 3. | +2 | 4. | +5 |
The oxidation state of two S-atoms in is:
1. +2 and +4
2. +3 and -2
3. +4 and -2
4. +6 and -2