Match Column I (Catalyst) with Column II (Process), and mark the appropriate option:
| Column I - (Catalyst) | Column II - (Process) | ||
| A. | Ni in the presence of hydrogen | 1. | Contact process |
| B. | Cu2Cl2 | 2. | Vegetable oil to ghee |
| C. | V2O5 | 3. | Sandmeyer reaction |
| D. | Finely divided iron | 4. | Haber's process |
| 5. | Decomposition of KClO3 |
Codes:
| A | B | C | D | |
| 1. | 3 | 4 | 2 | 5 |
| 2. | 2 | 3 | 1 | 4 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
Match Compound/element in Column-I with uses in Column-II and select the best match from the codes given:
| Column-I (Compound/element) |
Column-II (Uses) |
||
| A. | Lanthanoid oxide | I. | Petroleum cracking |
| B. | Lanthanoid | II. | Television screen |
| C. | Mischmetal | III. | Lanthanoid metal + iron |
| D. | Mixed oxides of lanthanoids are employed | IV. | Production of iron alloy |
| Options: | A | B | C | D |
| 1. | II | I | IV | III |
| 2. | I | II | III | IV |
| 3. | II | IV | III | I |
| 4. | IV | I | III | II |
Match the properties given in Column I with uses given in Column II
| Column I-(Property) | Column II-(Metal) | ||
| A. | An element that can show +8 oxidation state | 1. | Mn |
| B. | 3d block element that can show up to +7 | 2. | Cr |
| C. | 3d block element with the highest melting point | 3. | Os |
| 4. | Fe | ||
| A | B | C | |
| 1. | 3 | 1 | 2 |
| 2. | 1 | 2 | 3 |
| 3. | 1 | 4 | 3 |
| 4. | 4 | 2 | 3 |
Match the statements given in Column I with the oxidation states given in Column and mark the correct option.
| Column I | Column II | ||
| A. | Oxidation state of Mn in \(\mathrm{MnO}_2\) is | 1. | +2 |
| B. | Most stable oxidation state of Mn is | 2. | +3 |
| C. | Most stable oxidation state of Mn in oxides is | 3. | +4 |
| D. | Characteristic oxidation state of lanthanoids is | 4. | +5 |
| 5. | +7 |
| Options: | A | B | C | D |
| 1. | 2 | 3 | 4 | 1 |
| 2. | 3 | 1 | 5 | 2 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
Match the solutions given in Column I with the colours given in Column II.
| Column I (Aqueous solution of salt) |
Column II (Colour) |
||
| A. | FeSO4 .7H2O | 1. | Green |
| B. | NiCl2 . 4H2O | 2. | Light pink |
| C. | MnCl2.4H2O | 3. | Blue |
| D. | CoCl2. 6H2O | 4. | Pale green |
| 5. | Pink |
Codes:
| A | B | C | D | |
| 1. | 2 | 3 | 4 | 1 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 1 | 2 | 5 |
Match the property given in Column-I with the element given in Column-II.
|
Column-I (Property) |
Column-II (Element) |
||
| A. |
Lanthanoid which shows + 4 oxidation state |
1. |
Pm |
| B. |
Radioactive lanthanoid |
2. |
Ce |
| C. |
Lanthanoid which has 4 electronic configurations in +3 oxidation state |
3. |
Lu |
| D. |
Lanthanoid which has 4 electronic configurations in +3 oxidation state |
4. |
Gd |
| Options: | A | B | C | D |
| 1. | 2 | 4 | 1 | 3 |
| 2. | 1 | 2 | 3 | 4 |
| 3. | 2 | 1 | 4 | 3 |
| 4. | 4 | 1 | 3 | 2 |
Match the properties given in Column-I with the metals given in Column-II and mark the appropriate answer.
| Column-I (Property) | Column-II (Metal) | ||
| A. | Element with highest second ionisation enthalpy | i. | Co |
| B. | Element with highest third ionisation enthalpy | ii. | Cr |
| C. | M in \(\mathrm{M}(\mathrm{CO})_6\) is | iii. | Cu |
| D. | Element with highest heat of atomisation | iv. | Zn |
| v. | Ni |
| Assertion (A): | \(Cu^{2+}\) iodide is not known. |
| Reason (R): | \(Cu^{2+}\) oxidises \(I^-\) to iodine. |
| 1. | Both (A) and (R) are True, and (R) is the correct explanation of the (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is not True but (R) is True. |
| 4. | Both (A) and (R) are False. |
Given below are two statements:
| Assertion (A): | Separation of Zr and Hf is difficult. |
| Reason (R): | Because Zr and Hf lie in the same group of the periodic table. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is not true but (R) is true |
| 4. | Both (A) and (R) are false. |
| Assertion (A): | Actinoids form relatively less stable complexes as compared to lanthanoids. |
| Reason (R): | Actinoids can utilise their 5f orbitals along with 6d orbitals in bonding but lanthanoids do not use their 4f orbital for bonding. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is not True but (R) is True. |
| 4. | Both (A) and (R) are False. |