In Reimer-Tiemann reaction,
the product will be:
1. ortho-Salicylaldehyde
2. para-Salicylaldehyde
3. meta-Salicylaldehyde
4. All of the above
In Williamson ether synthesis, the major product would be:
1. 1-Methoxypropane
2. 2-Methoxypropane
3. 3-Methoxypropane
4. All of the above
Unsymmetrical ether will be the product in:
1. Kolbe’s reaction.
2. Reimer-Tiemann reaction.
3. Williamson ether synthesis.
4. None of the above.
In Kolbe’s reaction,
the product formed will be:
1. para-Salicylaldehyde
2. ortho-Salicylaldehyde
3. para-Salicylic acid
4. ortho-Salicylic acid
Match the following:
List I | List II | ||
i. | O2N-C6H5-OCH3 (p) | a. | 4-Ethoxy-1,1-dimethylcyclohexane |
ii. | C2H5OCH2-CH(CH3)2 | b. | 1-Chloro-2-methoxyethane |
iii. | CH3OCH2CH2Cl | c. | 1-Ethoxy-2-methylpropane |
iv. | d. | 1-Methoxy-4-nitrobenzene |
i | ii | iii | iv | |
1. | d | c | b | a |
2. | c | d | b | a |
3. | a | c | b | d |
4. | b | c | d | a |
Dehydration of ethanol in acidic medium yields:
1. Ethyne
2. Ethanol
3. Ethane
4. Ethene
In the following Williamson’s synthesis reaction,
CH3CH2ONa + CH3-Br → ?
The product will be:
1. | 1-Methoxyethane | 2. | 2-Methoxyethane |
3. | 3-Methoxyethane | 4. | 4-Methoxyethane |
The major product of Williamson’s ether synthesis reaction would be:
1. | Benzene | 2. | Methoxy benzene |
3. | Ethoxy benzene | 4. | Ethane |
The incorrect reaction among the following is:
1. | |
2. | |
3. | |
4. |
The major product of above Williamson's ether synthesis will be:
1. | 1-Propoxypropane | 2. | 2-Propoxypropane |
3. | 3-Propoxypropane | 4. | 4-Propoxypropane |