Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below: 
 
Then the species undergoing disproportionation is:-

In the electrochemical cell:

Zn|ZnSO₄(0.01 M) || CuSO₄(1.0M),Cu, the emf of this Daniel cell is E₁. When the concentration of ZnSO₄ is changed to 1.0 M and that of CuSO₄ is changed to 0.01 M, the emf changes to E₂. The relationship between E₁ and E₂ is : 
( Given, $\frac{RT}{\mathrm{F }}$= 0.059)

1. E₁ = E₂

2. E₁ < E₂

3. E₁ > E₂

4. E₂ = 0 $\ne$E₁

The molar conductivity of a solution of AgNO₃ (considering the given data for this solution) at 298 K is:
(a) Concentration: 0.5 mol/dm³
(b) Electrolytic conductivity: 5.76×10^–3 S cm^–1

During the electrolysis of molten sodium chloride, the time required to produce 0.10 mol of chlorine gas using a current of 3 amperes is

(1) 55 minutes                       

(2) 110 minutes

(3) 220 minutes                       

(4) 330 minutes

If the E°_cell for a given reaction has a negative value, which of the following gives correct relationships for the values of $∆$G° and K_eq ?

(1) $∆$G° >0;  K_eq< 1

(2) $∆$G° >0; K_eq>1

(3) $∆$G° < 0; K_eq> 1

(4) $∆$G° <0; K_eq< 1

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60 x 10^-19 C)

1. 6 x 10²³

2. 6 x 10²⁰

3. 3.75 x 10²⁰

4. 7.48 x 10²³

Zinc can be coated on iron to produce galvanised iron but the reverse is not possible. It is because

(1) zinc is lighter than iron

(2) zinc has lower melting point than iron

(3) zinc has lower negative electrode potential than iron

(4) zinc has higher negative electrode potential than iron

The molar conductivity of a 0.5 mol/dm³ solution of AgNO₃ with electrolytic conductivity of 5.76 × 10^–3 S cm^–1 at 298 K is:
1. 11.5 S cm²/mol
2. 21.5 S cm²/mol
3. 31.5 S cm²/mol
4. 41.5 S cm²/mol

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is:

(Charge on electron = 1.60 × 10^–19 C)

1.  $6\times {10}^{23}$

2.  $6\times {10}^{20}$

3.  $3.75\times {10}^{20}$

4.  $7.48\times {10}^{20}$

The pressure of H₂ required to make the potential of H₂ - electrode zero in pure water at 298 K is: