A bob is whirled in a horizontal plane by means of a string with an initial speed of \(\omega\) rpm. The tension in the string is \(T\). If speed becomes \(2\omega\) while keeping the same radius, the tension in the string becomes:
1.
\(4 T\)
2.
\(\dfrac{T}{4}\)
3.
\(\sqrt{2} T\)
4.
\(T\)
Subtopic: Uniform Circular Motion |
65%
Level 2: 60%+
NEET - 2024
Hints
Match List-I with List-II.
Choose the correct answer from the options given below:
| List-I Material |
List-II Susceptibility \((\chi)\) |
||
| \(\mathrm{(A)}\) | Diamagnetic | \(\mathrm{(I)}\) | \(\chi=0\) |
| \(\mathrm{(B)}\) | Ferromagnetic | \(\mathrm{(II)}\) | \(0>\chi\geq-1\) |
| \(\mathrm{(C)}\) | Paramagnetic | \(\mathrm{(III)}\) | \(\chi\gg1\) |
| \(\mathrm{(D)}\) | Non-magnetic | \(\mathrm{(IV)}\) | \(0<\chi<\varepsilon\) (a small positive number) |
| 1. | \(\text{A-II, B-I, C-III, D-IV}\) | 2. | \(\text{A-III, B-II, C-I, D-IV}\) |
| 3. | \(\text{A-IV, B-III, C-II, D-I}\) | 4. | \(\text{A-II, B-III, C-IV, D-I}\) |
Subtopic: Magnetic Materials |
67%
Level 2: 60%+
NEET - 2024
Hints
In the following circuit, the equivalent capacitance between terminal \(A\) and terminal \(B\) is:
| 1. | \(1~\mu\text F\) | 2. | \(0.5~\mu\text F\) |
| 3. | \(4~\mu\text F\) | 4. | \(2~\mu\text F\) |
Subtopic: Combination of Capacitors |
68%
Level 2: 60%+
NEET - 2024
Hints
A horizontal force \(10~\text N\) is applied to a block \(A\) as shown in figure. The mass of blocks \(A\) and \(B\) are \(2~\text{kg}\) and \(3~\text{kg}\), respectively. The blocks slide over a frictionless surface. The force exerted by block \(A\) on block \(B\) is :
1. \(4~\text N\)
2. \(6~\text N\)
3. \(10~\text N\)
4. zero
1. \(4~\text N\)
2. \(6~\text N\)
3. \(10~\text N\)
4. zero
Subtopic: Application of Laws |
69%
Level 2: 60%+
NEET - 2024
Hints
\({ }_{82}^{290} X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrightarrow{e^{-}} Q\)
In the nuclear emission stated above, the mass number and atomic number of the product \(Q\) respectively, are:
1. \(286,80\)
2. \(288,82\)
3. \(286,81\)
4. \(280,81\)
In the nuclear emission stated above, the mass number and atomic number of the product \(Q\) respectively, are:
1. \(286,80\)
2. \(288,82\)
3. \(286,81\)
4. \(280,81\)
Subtopic: Types of Decay |
67%
Level 2: 60%+
NEET - 2024
Hints
In a vernier callipers, \((N+1)\) divisions of the vernier scale coincide with \(N\) divisions of the main scale. If \(1\) \(\text{MSD}\) represents \(0.1~\text{mm}\), the vernier constant (in \(\text{cm}\)) is:
| 1. | \(\dfrac{1}{100(N+1)} \) | 2. | \(100N\) |
| 3. | \(10(N+1) \) | 4. | \(\dfrac{1}{10 N}\) |
Subtopic: Measurement & Measuring Devices |
71%
Level 2: 60%+
NEET - 2024
Hints
If \(x = 5 \mathrm {sin }\left(\pi t+ {\dfrac {\pi} 3}\right)~\text m\) represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively are:
| 1. | \(5~\text m, 2~\text s\) | 2. | \(5~\text {cm}, 1~\text s\) |
| 3. | \(5~\text m, 1~\text s\) | 4. | \(5~\text {cm}, 2~\text s\) |
Subtopic: Simple Harmonic Motion |
72%
Level 2: 60%+
NEET - 2024
Hints
In the above diagram, a strong bar magnet is moving towards solenoid-\(2\) from solenoid-\(1\). The direction of induced current in solenoid-\(1\) and that in solenoid-\(2\), respectively, are through the directions:
1. \(BA\) and \(CD\)
2. \(AB\) and \(CD\)
3. \(BA\) and \(DC\)
4. \(AB\) and \(DC\)
1. \(BA\) and \(CD\)
2. \(AB\) and \(CD\)
3. \(BA\) and \(DC\)
4. \(AB\) and \(DC\)
Subtopic: Faraday's Law & Lenz Law |
Level 3: 35%-60%
NEET - 2024
Hints
A logic circuit provides the output \(Y\) as per the following truth table:
The expression for the output \(Y\) is :
1. \(A \cdot \overline{B}+\overline{A} \)
2. \(\overline{B} \)
3. \(B \)
4. \(A \cdot B+\overline{A}\)
| \(A\) | \(B\) | \(Y\) |
| 0 0 1 1 |
0 1 0 1 |
1 0 1 0 |
1. \(A \cdot \overline{B}+\overline{A} \)
2. \(\overline{B} \)
3. \(B \)
4. \(A \cdot B+\overline{A}\)
Subtopic: Logic gates |
66%
Level 2: 60%+
NEET - 2024
Hints
A wire of length \('l'\) and resistance \(100 ~\Omega\) is divided into \(10\) equal parts. The first \(5\) parts are connected in series while the next \(5\) parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
| 1. | \(52~ \Omega\) | 2. | \(55~ \Omega\) |
| 3. | \(60 ~\Omega\) | 4. | \(26~ \Omega\) |
Subtopic: Combination of Resistors |
69%
Level 2: 60%+
NEET - 2024
Hints
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