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Displacement current is the same as:

The maxwell's equation:
$\oint \overrightarrow{B}.\overrightarrow{dl}={\mu }_0\left(i+{\epsilon }_0.\frac{d{\varphi }_E}{dt}\right)$ is a statement of :
(1) Faraday's law of induction
(2) Modified Ampere's law
(3) Gauss's law of electricity
(4) Gauss's law of magnetism

The charge of a parallel plate capacitor is varying as \(q = q_{0} \sin\omega t\). Find the magnitude of displacement current through the capacitor. 
(Plate Area = \(A\), separation of plates = \(d\))
1. \(q_{0}\cos \left(\omega t \right)\)
2. \(q_{0} \omega \sin\omega t\)
3. \(q_{0} \omega \cos \omega t\)
4. \(\frac{q_{0} A \omega}{d} \cos \omega t\)

The rate of change of the voltage of a parallel plate capacitor if the instantaneous displacement current of 1 A is established between the two plates of a 1 $\mu$F parallel plate capacitor:
1. ${10}^6 V/s$
2. 10 V/s
3. ${10}^8 V/s$ 
4. ${10}^{-6} V/s$

The relation between electric field E and magnetic field induction B in electromagnetic waves is given by:
(1) $E=\sqrt{\frac{{\mu }_0}{{\epsilon }_0}} B$
(2) E = cB
(3) E = $\frac{B}{c}$
(4) $E=\frac{B}{c^2}$

An electromagnetic wave is propagating along Y-axis. Then:
(1) The oscillating electric field is along X-axis and the oscillating magnetic field is along Y-axis.
(2) The oscillating electric field is along Z-axis and the oscillating magnetic field is along X-axis.
(3) Both oscillating electric and magnetic fields are along Y-axis, but the phase difference between them is ${90}^{°}$
(4) Both oscillating electric and magnetic fields are mutually perpendicular in arbitrary directions.

In electromagnetic wave the phase difference between electric and magnetic field vectors \(\vec E~\text{and}~\vec B\) is:
1. \(0\)
2. \(\frac{\pi}{2}\)
3. \(\pi\)
4. \(\frac{\pi}{4}\)

An electromagnetic wave going through the vacuum is described by $E=E_0\sin (kx-\omega t).$
Which is the following is/are independent of the wavelength?

In a plane EM wave, the electric field oscillates sinusoidally at a frequency of \(2.5\times 10^{10}~\text{Hz}\) and amplitude \(480\) V/m.  The amplitude of the oscillating magnetic field will be:
1. \(1.52\times10^{-8}~\text{Wb/m}^2\)
2. \(1.52\times10^{-7}~\text{Wb/m}^2\)
3. \(1.6\times10^{-6}~\text{Wb/m}^2\)
4. \(1.6\times10^{-7}~\text{Wb/m}^2\)

If ${\in }_0 and {\mu }_0$ represent the permittivity and permeability of vacuum and $\in and \mu$ represent the permittivity and permeability of the medium, then refractive index of the medium is given by :
(1) $\sqrt{\frac{{\in }_0{\mu }_0}{\in \mu }}$                 (2) $\sqrt{\frac{\in \mu }{{\in }_0{\mu }_0}}$
(3) $\sqrt{\frac{\in }{{\mu }_0{\in }_0}}$                  (4) $\sqrt{\frac{{\mu }_0{\in }_0}{\in }}$

The energy density of the electromagnetic wave in vacuum is given by the relation:
1. $\frac{1}{2}.\frac{E^2}{{\epsilon }_0}+\frac{B^2}{2{\mu }_0}$ 
2. $\frac{1}{2}{\epsilon }_0{E}^2+\frac{1}{2}{\mu }_0{B}^2$
3. $\frac{E^2+B^2}{C}$
4. $\frac{1}{2}{\epsilon }_0{E}^2+\frac{B^2}{2{\mu }_0}$

A lamp radiates power \(P_0\) uniformly in all directions. The amplitude of electric field strength \(E_0\) at a distance \(r\) from it is:
1. \(E_{0} = \frac{P_{0}}{2 \pi\varepsilon_{0} cr^{2}}\)
2. \(E_{0} = \sqrt{\frac{P_{0}}{2 \pi\varepsilon_{0} cr^{2}}}\)
3. \(E_{0} = \sqrt{\frac{P_{0}}{4 \pi\varepsilon_{0} cr^{2}}}\)
4. \(E_{0} = \sqrt{\frac{P_{0}}{8 \pi\varepsilon_{0} cr^{2}}}\)

The sun delivers ${10}^3 w/m^2$ of electromagnetic flux to the earth's surface.  The total power that is incident on a roof of dimensions 8 m$\times$20 m will be
(1) $2.56\times {10}^4 W$             (2) $6.4\times {10}^5 W$
(3) $4.0\times {10}^5 W$                (4) $1.6\times {10}^5 W$

The intensity of visible radiation at a distance of \(1\) m from a bulb of \(100\) W which converts only \(5\%\) of its power into light, is:
1. \(0.4\) W/m²
2. \(0.5\) W/m²
3. \(0.1\) W/m²
4. \(0.01\) W/m²

On an EM wave, the amplitude of electric and magnetic fields are 100 v/m and 0.265 A/m.  The maximum energy flow is
(1) 26.5 $W/m^2$           (2) 46.7 $W/m^2$
(3) 66.5 $W/m^2$            (4) 86.5 $W/m^2$

The most penetrating radiation out of the following is: 
(1) X-rays        (2) $\beta$-rays            (3) $\alpha$-rays           (4) $\gamma$-rays

1. A and B 
2. B and C
3. A, B and C
4. B only

The magnetic field in a plane EM wave traveling in the positive x-direction is given by 
$\mathrm{B}=\left(100\mathrm{\mu T}\right) \sin \left[\right(2\times {10}^{15}{\mathrm{s}}^{-1}\left)\right(\mathrm{t}-\mathrm{x}/\mathrm{c}\left)\right]\hat{\mathrm{j}}$
The equation for electric field is :
1. E=100sin [(2$\times {10}^{15}{s}^{-1})$(t-x/c)]$\left(-\hat{k}\right)$
2. E=(3$\times {10}^{10} \mu V/m$)sin [(2$\times {10}^{15}{s}^{-1})$(t-x/c)]$\left(-\hat{k}\right)$
3. E=3$\times {10}^{10}$sin [(2$\times {10}^{15}{s}^{-1})$(t-x/c)] $\hat{k}$
4. E=100sin [(2$\times {10}^{15}{s}^{-1})$(t-x/c)] $\hat{k}$

Statement I: A changing electric field produces a magnetic field.
Statement II: A changing magnetic field produces an electric field.
(1) If both statement-I and Statement-II are true, and Statement-II is the correct explanation of Statement-I.
(2) If both Statement-I and Statement-II are true but Statement-II is not the correct explanation of Statement-I.
(3) If Statement-I is true but Statement-II is false.
(4) If Statement-I is false but Statement-II is true.

Statement-I: Gamma rays are more energetic than X-rays.
Statement-II: Gamma rays are of nuclear origin but X-rays are produced due to sudden deceleration of high energy electrons while falling on a metal of high atomic number.
(1) If both statement-I and Statement-II are true, and Statement-II is the correct explanation of Statement-I.
(2) If both Statement-I and Statement-II are true but Statement-II is not the correct explanation of Statement-I.
(3) If Statement-I is true but Statement-II is false.
(4) If Statement-I is false but Statement-II is true.