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The order of melting point for isomeric pentanes is
1. n-pentane > Isopentane > Neopentane
2. Neopentane > Isopentane > n-pentane
3. Neopentane > n-pentane > Isopentane
4. Isopentane > n-pentane > Neopentane

${\mathrm{CH}}_3$
$|$
${\mathrm{CH}}_3 - \mathrm{CH} - {\mathrm{CH}}_2 - \underset{\mathrm{Mole}}{\mathrm{Cl}} \stackrel{\mathrm{hv}}{\to } \mathrm{A}\left(\mathrm{major}\right)$
The compound ‘A’ is
1. ${\mathrm{CH}}_3$
$|$
${\mathrm{CH}}_3 - \mathrm{CH} - {\mathrm{CH}}_2 - \mathrm{Cl}$
2. ${\mathrm{CH}}_3$
$|$
${\mathrm{CH}}_3 - \mathrm{CH} - {\mathrm{CH}}_2$
$|$
$\mathrm{Cl}$
3. Both (1) and (2)
4. Neither (1) nor (2)

Which haloarene gives the fastest electrophilic substitution reaction?
1. 
2. 
3. 
4. 

In the nitrating mixture $({\mathrm{H}}_2{\mathrm{SO}}_4 \mathrm{and} {\mathrm{HNO}}_3), {\mathrm{HNO}}_3$ acts as 
1. Acid
2. Base
3. Acid as well as base
4. Neither acid nor base

Compound 'A' and 'B' respectively
1. Both are C is-butene-2
2. Cis-butene-2, Trans-butene-2
3. Both are Trans-butene-2
4. Trans-butene-2, C is-butene-2
 

1. 
2. 
3. 
4. 

                    
The ease of aromatic nucleophilic substitution among these compounds will be in the order as:
1. IV > I > II > III
2. IV > III > II > I
3. III > II > IV > I
4. I > II > III > IV

When chloroform is reacted with an excess of NaOH then final product formed is
1. HCOOH
2. ${\mathrm{CH}}_3\mathrm{COOH}$
3. ${\mathrm{CH}}_3\mathrm{COONa}$
4. HCOONa

1. 
2. 
3. 
4. 

Which haloarenes is most reactive towards electrophilic substitution reaction?
1. 
2. 
3. 
4. 

Among the following bromides given below, the order of their reactivity in the ${\mathrm{S}}_{\mathrm{Nl}}$ the reaction is:
                     
1. III > II > I 
2. II > III > I
3. III > I > II
4. II > I > III

Replacement of 'Cl of chlorobenzene to give phenol requires drastic conditions but chlorine of 2,4-dinitrochloro benzene is readily replaced because
1. ${\mathrm{NO}}_2$ makes the ring electrons rich at ortho and para position
2. ${\mathrm{NO}}_2$ withdraws electrons from meta-position
3. ${\mathrm{NO}}_2$ donates electrons at m-position
4. ${\mathrm{NO}}_2$ withdraws electrons from ortho and para positions

Arrange the following halides in the decreasing order of ${\mathrm{S}}_{\mathrm{N}}\mathrm{l}$ reactivity
(I) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Cl}$
(II) ${\mathrm{CH}}_2 = \mathrm{CHCH}\left(\mathrm{Cl}\right){\mathrm{CH}}_3$
(III) ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}\left(\mathrm{Cl}\right){\mathrm{CH}}_3$
1. I > II > III
2. II > I > III
3. II > III > I
4. III > II > I

The correct order of solvolysis in the following alkyl halide is
1. 
2. 
3. 
4. 

On monochlorination of 2-methyl butane, the total number of chiral compounds is
1. 2
2. 4
3. 6
4. 8