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The order of melting point for isomeric pentanes is
 
1. n-pentane> Isopeitane > Neopentane
2. Neopentaiie > Isopentane > n-pentane
3. Neopentane > n-pelitalie > Isopentane
4. Isopentane > n-pentane > Neopentane

1. 
2. 
3. Both (1) and (2)
4. Neither (1) nor (2)

Which haloarene gives fastest electrophilic substitution reaction?
 
1. 
2. 
3. 
4. 

In the nitrating mixture ($H_{2}S{O}_4$ and $HN{O}_3$), $HN{O}_3$ acts as
1. Acid
2. Base
3. Acid as well as base
4. Neither acid nor base

Compound ‘A’ and ‘B’ respectively
 
1. Both are C’is-butene-2
2. Cis -butene- 2, Trans-butene-2
3. Both are Trans-butene-2
4. Trans -butene- 2, Cis-butene-2

(A) and (B) are respectively :
1. 
2. 
3. 
4. 

The ease of aromatic nucleophilic substitution among these compounds will be in the order as :
1. IV > I > II >III
2. IV > III > II > I
3. III > II > IV >I
4. I > II > III > IV 

When chloroform is reacted with excess of NaOH then final product formed is 
1. HCOOH
2. ${\mathrm{CH}}_3\mathrm{COOH}$
3. ${\mathrm{CH}}_3\mathrm{COONa}$
4. HCOONa

$\underset{\mathrm{peroxide}}{\overset{\mathrm{HCl}}{\to }}M; Mis$

Which haloarenes is most reactive towards electrophilic substitution reaction ?

Among the following bromides given below, the order of their reactivity in the S_N1 reaction is 

1. III > II > I
2. II > III > I
3. III > I > II
4. II > I > III

Replacement of 'Cl' of  chlorobenzene to give phenol requires drastic conditions but chlorine of 2,4- dinitrochloro benzene is readily replaced because
1. ${\mathrm{NO}}_2$ makes the ring electrons rich at ortho and para position
2. ${\mathrm{NO}}_2$ withdraws electrons from meta position
3. ${\mathrm{NO}}_2$ donates electrons at m-position
4. ${\mathrm{NO}}_2$ withdraws electrons from ortho and para positions 

Arrange the following halides in the decreasing order of S_N1 reactivity 
(I) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Cl}$
(II) ${\mathrm{CH}}_2=\mathrm{CHCH}\left(\mathrm{Cl}\right){\mathrm{CH}}_3$
(III) ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}\left(\mathrm{Cl}\right){\mathrm{CH}}_3$
1. I > II > III
2. II > I > III
3. II > III > I
4. III > II > I

The correct order of solvolysis in the following alkyl halide is -

On monochlorination of 2-methylbutane, the total number of chiral compounds is 
1. 2
2. 4
3. 6
4. 8