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1.

The final product C in the below mentioned reaction is:
\(\xrightarrow[]{Ac_2O}\ A\ \xrightarrow[CH_3COOH]{Br_2}\ B\ \xrightarrow[H^+]{H_2O}\ C\)

1.		2.
3.		4.

2.

1.
2.
3.
4.	All of these

3.

An aromatic amine (A) was treated with alcoholic potash and another compound (Y) when a foul smelling gas was formed with formula C₆H₅NC. (Y) was formed by reacting a compound (Z) with Cl₂ in the presence of slaked lime. Compound (Z) is:
1. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2$
2. ${\mathrm{CH}}_3\mathrm{OH}$
3. ${\mathrm{CH}}_3{\mathrm{COCH}}_3$
4. ${\mathrm{CHCl}}_3$

4.

Mark the reaction that does not yield aniline from the given options:

1.	Hydrolysis of phenyl isocyanide with an acidic solution
2.	Degradation of benzamide with bromine in alkaline solution
3.	Reduction of nitrobenzene with H2/Pd in ethanol
4.	Treatment of Potassium salt of phthalimide with chlorobenzene followed by hydrolysis in an aqueous NaOH solution

5.

What results from the electrolytic reduction of nitrobenzene in a highly acidic medium?
1. p-Aminophenol
2. Azoxybenzene
3. Azobenzene
4. Aniline

6.

Nitrobenzene on reaction with conc. HNO₃ /H₂SO₄ at 80 – 100 ºC forms:
1. 1,3– Dinitrobenzene
2. 1,4–Dinitrobenzene
3. 1,2,4–Trinitrobenzene
4. 1,2–Dinitrobenzene

7. What is the correct order of the methyl-substituted amines' basic strength in an aqueous solution?
1. CH₃NH₂ > (CH₃)₂NH > (CH₃)₃N
2. (CH₃)₂NH > CH₃NH₂ > (CH₃)₃N
3. (CH₃)₃N > CH₃NH₂ > (CH₃)₂NH
4. (CH₃)₃N > CH₃NH₂ > (CH₃)₂NH

8.

$\underset{\left(2\right){\mathrm{Br}}_2/\mathrm{KOD}}{\overset{\left(1\right){\mathrm{NH}}_3,∆}{\to }}A,\left(Major\right)$
The product ‘A’ is

9.

$\underset{0°-5°\mathrm{C}}{\overset{{\mathrm{NaNO}}_2+\mathrm{HCl}}{\to }}$X moles of ${\mathrm{N}}_2$ gas
Hence, the value of ‘X’ is
1. 4
2. 3
3. 2
4. 1

10.

Aniline    o-toluidine     m-toluidine    p-toluidine
(I)              (II)               (III)              (IV)
Correct order of basic strength of the above
compounds is
1. II > IV > III > I
2. IV > III > I > II
3. III > II > IV > I
4. IV > I > III > II

11.

Consider the following reaction,

Choose the correct alternatives about the product(P)
1. Product P contains a cyclic ring with one $\mathrm{\pi }$ -bond
2. Product P has an open chain with only one $\mathrm{\pi }$ -
bond
3. N-atom in the product is sp² -hybridised.
4. Product P could be 

12.

The final product in the following sequence of reaction
is:
$\stackrel{{\mathrm{Br}}_2/{\mathrm{OH}}^{-}}{\to }\underset{HCl}{\overset{NaN{O}_2}{\to }}\stackrel{HB{F}_4}{\to }$