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When a lead storage battery is discharged, then:
1. SO₂ is evolved.
2. Lead is formed.
3. Lead sulphate is consumed.
4. Sulphuric acid is consumed.

The E° in the given diagram is,

(1) 0.5
(2) 0.6
(3) 0.7
(4) 0.8

One gm metal $M^{3+}$ was discharged by the passage of 1.81 x ${10}^{23}$ electrons.
What is the atomic weight of metal?
1. 33.35
2. 133.4
3. 66.7
4. None of these

 If ${E^0}_{A{u}^{+}/Au}$ is 1.69 V and ${E^0}_{A{u}^{3+}/Au}$ is 1.40 V, then ${E^0}_{A{u}^{+3}/A{u}^{1+}}$ will be :
1. 0.19 V
2. 2.945 V
3. 1.255 V
4. None of these

Equivalent conductivity of ${\mathrm{Fe}}_2{\left({\mathrm{SO}}_4\right)}_3$is related to molar conductivity by the expression:
1. ${\wedge }_{eq}$ = ${\wedge }_m$
2. ${\wedge }_{eq}$ = ${\wedge }_m/3$
3. ${\wedge }_{eq}$ = $3{\wedge }_m$
4. ${\wedge }_{eq}$ = ${\wedge }_m/6$

For a reaction A(s) + 2B⁺ $\to$ A²⁺ + 2B(s) ;  K_C has been found to be 10¹². The ${\mathrm{E}}_{\mathrm{cell}}^{°}$ is : 

In the Hall process, aluminium is produced by the electrolysis of molten ${\mathrm{Al}}_2{\mathrm{O}}_3$ by the following reactions. How many second would it take to produce enough aluminum by the Hall process to make a case of 24 cans of aluminium soft-drink, if each can uses 5.0 g of Al, a current of 9650 amp is employed, and the current efficiency of the cell is 90.0%:
(1) 203.2
(2) 148.14
(3) 333
(4) 6.17

Consider the reaction given below:
$2{\mathrm{CH}}_3{\mathrm{COO}}^{-}\to {\mathrm{C}}_2{\mathrm{H}}_6\left(\mathrm{g}\right)+2{\mathrm{CO}}_2\left(\mathrm{g}\right)+2{\mathrm{e}}^{-}$
The electrolysis of acetate solution produces ethane. The current efficiency of the process is 80%. What volume of gases would be produced at 27$°\mathrm{C}$ and 740 torr, if the current of 0.5 amp is passed through the solution for 96.45 min?
1. 6.0 L
2. 0.60 L
3. 1.365 L
4. 0.91 L

$\Delta f{H^{\circ }}_{298}+T.\Delta {S^{\circ }}_{298}=(-474.78)+298\times (-0.32)$
$\Delta f{H^{\circ }}_{298}=-378.07kJ/mol$
Given: ${\mathrm{O}}_2\left(\mathrm{g}\right)+4{\mathrm{H}}^{+}\left(\mathrm{aq}\right)+4{\mathrm{e}}^{-}\to 2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right);\mathrm{E}°=1.23 \mathrm{V}$
(1) -285.07 kJ/mol
(2) -570.14 kJ/mol
(3) 285.07 kJ/mol
(4) None of these

Equivalent conductivity of ${\mathrm{BaCl}}_2, {\mathrm{H}}_2{\mathrm{SO}}_4 \mathrm{and} \mathrm{HCl} \mathrm{are} {\mathrm{x}}_1, {\mathrm{x}}_2 \mathrm{and} {\mathrm{x}}_3 {\mathrm{Scm}}^{-1} {\mathrm{eq}}^{-1}$ at infinite dilution. If conductivity of saturated ${\mathrm{BaSO}}_4$ solution is x ${\mathrm{Scm}}^{-1}, \mathrm{then} {\mathrm{K}}_{\mathrm{sp}} \mathrm{of} {\mathrm{BaSO}}_4$ is:
(1) $\frac{500\mathrm{x}}{({\mathrm{x}}_1+{\mathrm{x}}_2-2{\mathrm{x}}_3)}$
(2) $\frac{{10}^6{\mathrm{x}}^2}{{\left({\mathrm{x}}_1+{\mathrm{x}}_2-2{\mathrm{x}}_3\right)}^3}$
(3) $\frac{2.5\times {10}^5{\mathrm{x}}^2}{{\left({\mathrm{x}}_1+{\mathrm{x}}_2-{\mathrm{x}}_3\right)}^2}$
(4)  $\frac{0.25{\mathrm{x}}^2}{{\left({\mathrm{x}}_1+{\mathrm{x}}_2-{\mathrm{x}}_3\right)}^2}$

The ionization constant of a weak acid is $1.6\times {10}^{-5}$ and the molar conductivity at infinite dilution is $380\times {10}^{-4} {\mathrm{Sm}}^2 {\mathrm{mol}}^{-1}$. If the cell constant is 0.01 ${\mathrm{m}}^{-1}$ then conductance of 0.01 M acid solution is:
(1) $1.52\times {10}^{-5} \mathrm{s}$
(2) 1.52 s
(3) $1.52\times {10}^{-3} \mathrm{s}$
(4) $1.52\times {10}^{-4} \mathrm{s}$