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Identify ‘Y’ in
$\underset{\mathrm{oxidation}}{\overset{\mathrm{vigorous} }{\to }}\mathrm{X}\underset{\mathrm{heating}}{\overset{\mathrm{Dry}}{\to }}\mathrm{Y}$

 

In a Cannizzaro’s reaction, the intermediate that
will be the best hydride donor is

On warming with I₂ and aqueous NaOH,
iodoform and sodium succinate are formed. The
formula of the compound should be
1. CH₃COCH₂CH₂CH₃
2. CH₃COC₆H₅
3. ${\mathrm{CH}}_3{\mathrm{COCH}}_2{\mathrm{CH}}_2{\mathrm{COCH}}_3$
4. none of these.

An amide (A) C₃H₇NO on hydrolysis gives an
amine (B) and an acid (C). B gives carbylamine
reaction where as C reduces Tollen’s reagent.
(A) is
1. CH₃CONHCH₃
2. CH₃CH₂CONO₂
3. HCONHC₂H₅
4. $\mathrm{HCON}{\left({\mathrm{CH}}_3\right)}_2$

The appropriate reagent for the transformation
is

1. Zn (Hg)/HCl
2. NH₂ – NH₂ / OH^–
3. Both 1. and 2.
4. None of the above

Identify the product (c) in the series
${\mathrm{CH}}_3\mathrm{CN}\stackrel{\mathrm{Na}/{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}{\to }\mathrm{A}\stackrel{{\mathrm{HNO}}_2}{\to }\mathrm{B}\stackrel{{\mathrm{KMnO}}_4,{\mathrm{H}}^{+}}{\to }\mathrm{C}$
1. CH₃COOH
2. CH₃CH₂NHOH
3. CH₃CONH₂
4. CH₃CHO

In the reaction
CH3 – CH = CH – CHO$\underset{\mathrm{agent}}{\overset{\mathrm{oxidizing}}{\to }}$ ${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{COOH}$ 
the oxidizing agent can be
1. alkaline KMnO₄
2. acidified K₂Cr₂O₇
3. benedict’s solution
4. All of the above
 

When propanoic acid is treated with aqueous
sodium bicarbonate, CO₂ is liberated. The ‘C’
of CO₂ comes from
1. carboxylic acid group
2. methylene group
3. bicarbonate
4. methyl group

Among the following acids, which one has the smallest dissociation constant?

1.		2.
3.		4.

$\mathrm{R}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{OH}\to \mathrm{R}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{COOH}$ 
The correct sequence of reagents for the above transformation is-
1. PBr₃, KCN, H₃O⁺
2. PBr₃, KCN, H₂
3. KCN, H₃O⁺
4. HCN, PBr₃, H₃O⁺

The correct statement among the following about HCOOH is:
1. It is a stronger acid than CH₃COOH
2. It reduces Tollen’s reagent
3. It gives CO and H₂O on heating with conc.H₂SO₄
4. All of the above

What results from a reaction between concentrated H₂SO₄ and acetone?
1. Phorone
2. Mesitylene
3. Mesityl oxide
4. Crotonaldehyde

Which carboxylic acid is least reactive
towards decarboxylation on heating?

$\underset{{\mathrm{H}}_3{\mathrm{O}}^{\odot }}{\overset{{\mathrm{CH}}_3\mathrm{MgBr}\left(\mathrm{excess}\right)}{\to }}$(X)
What is X?

The end product of the following reaction would
be
$\underset{\left(\mathrm{ii}\right)∆}{\overset{\left(\mathrm{i}\right) {\mathrm{H}}_3{\mathrm{O}}^{\oplus }}{\to }}$

The correct order of increasing reactivity
towards acid hydrolysis is
$\underset{\left(1\right)}{{\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5} \underset{\left(2\right)}{{\mathrm{CH}}_3\mathrm{COCl}} \underset{\left(3\right)}{{\mathrm{CH}}_3{\mathrm{CONHCH}}_3}$
1. 1 < 2 < 3
2. 3 < 1 < 2
3. 1 < 3 < 2
4. 2 < 1 < 3

 $\underset{\left(2\right) {\mathrm{Br}}_2/\mathrm{KOD}}{\overset{\left(1\right) {\mathrm{NH}}_3,∆}{\to }}$A(Major)
The product 'A' is 

$\underset{{\mathrm{OH}}^{-}}{\overset{\mathrm{dilute}}{\to }}$ ?
The major product formed would be:

1.
2.
3.
4.