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#23-Solved-Examples-13
(Physics) > Motion in A Straight Line

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Related Practice Questions :

The acceleration of a moving body can be found from: 

(1) Area under the velocity-time graph

(2) Area under the distance-time graph

(3) Slope of the velocity-time graph

(4) Slope of the distance-time graph

 75%
From NCERT
PMT - 1981
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A particle starts from rest. Its acceleration \((a)\) versus time \((t)\) is as shown in the figure. The maximum speed of the particle will be: 

             
1. \(110~\text{m/s}\)
2. \(55~\text{m/s}\)
3\(550~\text{m/s}\)
4. \(660~\text{m/s}\)

 73%
From NCERT
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The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The distance travelled by the particle in four seconds is 

1. 60 m

2. 55 m

3. 25 m

4. 30 m

 85%
From NCERT
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The displacement of a particle as a function of time is shown in the figure. The figure shows that
                      
1. The particle starts with certain velocity but the motion is retarded and finally the particle stops
2. The velocity of the particle is constant throughout
3. The acceleration of the particle is constant throughout
4. The particle starts with constant velocity, then motion is accelerated and finally the particle moves with another constant velocity

 65%
From NCERT
PMT - 1970
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The graph between the displacement \(x\) and time \(t\) for a particle moving in a straight line is shown in the figure.


During the interval OA, AB, BC and CD the acceleration of the particle is:

OA AB BC CD
1. + 0 + +
2. 0 + 0
3. + 0 +
4. 0 0
 50%
From NCERT
PMT - 1986
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