CrO42- (yellow) changes to Cr2O72- (orange) in pH = x and vice versa in pH = y.
The value of x and y will be:
1. 6, and 8
2. 6, and 5
3. 8, and 6
4. 7, and 7
The colour of KMnO4 is due to :
1. d-d transition
2. Charge transfer spectra
3. Polarisation of ion
4. p-d transition
Cr2O72-+XCr3++H2O + oxidized product of X. X in the above reaction cannot be
1. C2O42-
2. Fe2+
3. SO42-
4. S2-
In the dichromate ion Cr2O72-,
1. 4 Cr-O bonds are equivalent
2. 6 Cr-O bonds are equivalent
3. All Cr-O bonds are equivalent
4. None of Cr-O bonds are equivalent
Name the gas that can readily decolourise acidified KMnO4 solution.
(1) CO2
(2) SO2
(3) NO2
(4) P2O5