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#6 | Nernst Equation
(Chemistry) > Electrochemistry

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Related Practice Questions :

Which is the correct representation for Nernst equation ?

1. \(E_{\mathrm{RP}}=E_{\mathrm{RP}}^{\circ}+\frac{0.059}{\mathrm{n}} \log \frac{[\text { oxidant }]}{[\text { reductant }]}\)

2. \(E_{\mathrm{OP}}=E_{\mathrm{OP}}^{\circ}-\frac{0.059}{\mathrm{n}} \log \frac{[\text { oxidant }]}{[\text { reductant }]}\)

3. \(E_{\mathrm{OP}}=E_{\mathrm{OP}}^{\circ}+\frac{0.059}{\mathrm{n}} \log \frac{[\text { reductant }]}{[\text { oxidant }]}\)

4. All of the above

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The voltage of the cell given below increases with: 

Cell: Sn(s) + 2Ag+(aq) → Sn2+(aq) + 2Ag(s)

1. Increase in size of the silver rod.

2. Increase in the concentration of Sn2+ ions.

3. Increase in the concentration of Ag+ ions.

4. None of the above.

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Which graph correctly correlates Ecell as a function of concentrations for the cell (for different values of M and M') ?

Zn(s) + Cu2+(M)           Zn2+(M') + Cu(s);
                Ecell = 1.10 V
X-axis : log10Zn2+Cu2+, Y-axis : Ecell 

1.                         2. 
3.                         4. 

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The solution of CuSO4 in which copper rod is immersed is diluted to 10 times, the reduction electrode potential:

1. increases by 0.030 V

2. decreases by 0.030 V

3. increases by 0.059 V

4. decreases by 0.059 V

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The change in reduction potential of a hydrogen electrode when its solution initialy at pH = 0 is neutralised to pH = 7, is a/an-

1. Increase by 0.059 V 2. Decrease by 0.059 V
3. Increase by 0.41 V 4. Decrease by 0.41 V
 52%
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