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#32 | Question Set4: Beats
(Physics) > Waves

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Eleven tuning forks are arranged in increasing order of frequency in such a way that any two consecutive tuning forks produce \(4\) beats per second. The highest frequency is twice that of the lowest. The highest and the lowest frequencies (in Hz) are, respectively:
1. \(100~\text{and}~50\) 2. \(44~\text{and}~22\)
3. \(80~\text{and}~40\) 4. \(72~\text{and}~30\)
 67%
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A source of unknown frequency gives 4 beats/s when sounded with a source of known frequency 250 Hz. The second harmonic of the source of unknown frequency gives five beats per second when sounded with a source of frequency 513 Hz. The unknown frequency is

(1) 254 Hz

(2) 246 Hz

(3) 240 Hz

(4) 260 Hz

 75%
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NEET - 2013
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Two sources of sound placed close to each other, are emitting progressive waves given by

y1=4 sin 600πt and y2=5 sin 608 πt

An observer located near these two sources of sound will hear

(a)4 beats per second with intensity ratio 25:16 between waxing and waning

(b) 8 beats per second with intensity ratio 25:16 between waxing and waning

(c) 8 beats per second with intensity ratio 81:1 between waxing and waning

(d) 4 beats per second with intensity ratio 81:1 waxing and waning

 54%
From NCERT
NEET - 2012
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Two identical piano wires kept under the same tension \(T\) have a fundamental frequency of \(600~\text{Hz}\). The fractional increase in the tension of one of the wires which will lead to the occurrence of \(6\) beats/s when both the wires oscillate together would be:
1. \(0.02\) 2. \(0.03\)
3. \(0.04\)  4. \(0.01\)
 54%
From NCERT
NEET - 2011
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A tuning fork of frequency \(512~\text{Hz}\) makes \(4\) beats/s with the vibrating strings of a piano. The beat frequency decreases to \(2\) beats/s when the tension in the piano strings is slightly increased. The frequency of the piano string before increasing the tension was:
1. \(510~\text{Hz}\)
2. \(514~\text{Hz}\)
3. \(516~\text{Hz}\)
4. \(508~\text{Hz}\)
 70%
From NCERT
NEET - 2010
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