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#3 | Electromotive Force
(Physics) > Current Electricity

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Related Practice Questions :
A battery has emf \(4\) V and internal resistance \(r\). When this battery is connected to an external resistance of \(2\) ohm, a current of \(1\) ampere flows in the circuit. How much current will flow if the terminals of the battery are connected directly?
1. \(1\) A 2. \(2\) A
3. \(4\) A 4. Infinite
 66%
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In the circuit shown below, the cell has an e.m.f. of 10 V and internal resistance of 1 ohm. The other resistances are shown in the figure. The potential difference VAVB is :

1. 6 V

2. 4 V

3. 2 V

4. –2 V

 56%
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PMT - 1997
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In the circuit, the potential difference across PQ will be nearest to 

1. 9.6 V

2. 6.6 V

3. 4.8 V

4. 3.2 V

 70%
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The e.m.f. of a cell is E volts and internal resistance is r ohm. The resistance in external circuit is also r ohm. The p.d. across the cell will be 

1. E/2

2. 2E

3. 4E

4. E/4

 82%
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PMT - 1985
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The terminal potential difference of a cell when short-circuited is (E = E.M.F. of the cell)

1. E

2. E/2

3. Zero

4. E/3

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