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#14 | Grouping of Resistors (Method of Common Potential)
(Physics) > Current Electricity

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The current \(I\) as shown in the circuit will be:

1. \(10~\text{A}\) 2. \(\dfrac{20}{3}~\text{A}\)
3. \(\dfrac{2}{3}~\text{A}\) 4. \(\dfrac{5}{3}~\text{A}\)
 61%
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The potential difference between points A and B of the adjoining figure is

1. 23V

2. 89V

3. 43V

4. 2 V

 57%
PMT - 1991
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Two resistors of resistance R1 and R2 having R1 > R2 are connected in parallel. For equivalent resistance R, the correct statement is :

1. R>R1+R2

2. R1<R<R2

3. R2<R<(R1+R2)

4. R < R1

 66%
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PMT - 1978
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A wire of resistance \(R\) is divided into \(10\) equal parts. These parts are connected in parallel, the equivalent resistance of such connection will be:
1. \(0.01R\)
2. \(0.1R\)
3. \(10R\)
4. \(100R\)

 64%
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PMT - 1973
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Three resistors each of 2 ohm are connected together in a triangular shape. The resistance between any two vertices will be 

1. 4/3 ohm

2. 3/4 ohm

3. 3 ohm

4. 6 ohm

 83%
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PMT - 1983
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