If a resistance R₂ is connected in parallel with the resistance R in the circuit shown, then possible value of current through R and the possible value of R₂ will be

(1) $\frac{I}{3},R$

(2) $I,2R$

(3) $\frac{I}{3},R$

(4) $\frac{I}{2},R$

A battery of emf \(10\) V is connected to resistance as shown in the figure below. The potential difference \(V_{A} - V_{B}\)
between the points \(A\) and \(B\) is:

1. \(-2\) V

2. \(2\) V

3. \(5\) V

4. \(\frac{20}{11}~\text{V}\)

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A. then the resistance of the resistor will be 

(1) 19 Ω

(2) 17 Ω

(3) 10 Ω

(4) 12 Ω

In the circuit shown below, The reading of the voltmeter V is 

(1) 12 V

(2) 8 V

(3) 20 V

(4) 16 V

In circuit shown below, the resistances are given in ohms and the battery is assumed ideal with emf equal to \(3\) volt. The voltage across the resistance \(R_4\) is:

1. \(0.4\) V
2. \(0.6\) V
3. \(1.2\) V
4. \(1.5\) V