The quantum number not obtained from Schrodinger’s wave equation is:

1.	\(n\)	2.	\(l\)
3.	\(m\)	4.	\(s\)

For a subatomic particle, the uncertainty in position is same as that of uncertainty in its momentum. The
least uncertainty in its velocity can be given as-

1. $∆\mathrm{V} = \frac{\mathrm{h}}{4{\mathrm{\pi m}}^2}$

2. $∆\mathrm{V} = \frac{1}{2\mathrm{\pi }}\sqrt{\frac{\mathrm{h}}{\mathrm{m}}}$

3. $∆\mathrm{V} = \frac{\mathrm{h}}{2\mathrm{\pi m}}$

4. $∆\mathrm{V} = \frac{1}{2\mathrm{m}}\sqrt{\frac{\mathrm{h}}{\mathrm{\pi }}}$

Each questions contains STATEMENT-1 (Assertion) and STATEMENT2- (Reason).

Examine the statements carefully and mark the correct answer according to the instructions given below:

Statement-1: Orbital having xz plane as node may be 3d_xy.

Statement-2: 3d_xy has zero radial node.

1.  If both the statement are true and statement -2 is the correct explanation of statement-1

2.  If both the statements are true but statement-2 is not the correct explanation of statement-1

3.  If statement-1 is true and statement-2 is false

4.  If statement-1 is false and statement-2 is true

Statement 1: The ground state electronic configuration of nitrogen is

Statement 2: Electrons are filled in orbitals as per the Aufbau principle, Hund's rule of maximum spin multiplicity, and Pauli's principle.

1.  If both the statement are true and statement -2 is the correct explanation of statement-1

2.  If both the statements are true but statement-2 is not the correct explanation of statement-1

3.  If statement-1 is true and statement-2 is false

4.  If statement-1 is false and statement-2 is true

Given below are two statements:

A dye absorbs a photon of wavelength $\mathrm{\lambda }$ and re-emits the same energy into two photons of wavelengths ${\mathrm{\lambda }}_1$ $$ and ${\mathrm{\lambda }}_2$ respectively. The wavelength $\mathrm{\lambda }$ is related to ${\mathrm{\lambda }}_1$ and ${\mathrm{\lambda }}_2$ as:

1.  $\mathrm{\lambda }=\frac{{\mathrm{\lambda }}_1+{\mathrm{\lambda }}_2}{{\mathrm{\lambda }}_1{\mathrm{\lambda }}_2}$

2.  $\mathrm{\lambda }=\frac{{\mathrm{\lambda }}_1{\mathrm{\lambda }}_2}{{\mathrm{\lambda }}_1+{\mathrm{\lambda }}_2}$

3.  $\mathrm{\lambda }=\frac{{\mathrm{\lambda }}_1^2+{\mathrm{\lambda }}_2^2}{{\mathrm{\lambda }}_1+{\mathrm{\lambda }}_2}$

4.  $\mathrm{\lambda }=\frac{{\mathrm{\lambda }}_1{\mathrm{\lambda }}_2}{{\left({\mathrm{\lambda }}_1+{\mathrm{\lambda }}_2\right)}^2}$

The excited state of an H atom emits a photon of wavelength $\mathrm{\lambda }$ and returns to the ground state. The principal quantum number of the excited state is given by:

1.  $\sqrt{\mathrm{\lambda R}\left(\mathrm{\lambda R}-1\right)}$

2.  $\sqrt{\frac{\mathrm{\lambda R}}{\left(\mathrm{\lambda R}-1\right)}}$

3.  $\sqrt{\mathrm{\lambda R}\left(\mathrm{\lambda R}+1\right)}$

4.  $\sqrt{\frac{\left(\mathrm{\lambda R}-1\right)}{\mathrm{\lambda R}}}$

Identify the graph that correctly depicts the variation of momentum with the de-Broglie wavelength of a particle. 

1.		2.
3.		4.

 $\sqrt{\mathrm{V}}$on two particles A and B are plotted against de-Broglie wavelengths. Where V is the potential on the particles. Which of the following relation is correct about the mass of particles?

1.  ${\mathrm{m}}_{\mathrm{A}}={\mathrm{m}}_{\mathrm{B}}$

2.  ${\mathrm{m}}_{\mathrm{A}}>{\mathrm{m}}_{\mathrm{B}}$

3.  ${\mathrm{m}}_{\mathrm{A}}<{\mathrm{m}}_{\mathrm{B}}$

4.  ${\mathrm{m}}_{\mathrm{A}}\le {\mathrm{m}}_{\mathrm{B}}$