Displacement current is the same as:

1.	Conduction current due to the flow of free electrons
2.	Conduction current due to the flow of positive ions
3.	Conduction current due to the flow of both positive and negative free charge carriers
4.	It is not a conduction current but is caused by the time-varying electric field

The charge of a parallel plate capacitor is varying as; \(q = q_{0} \sin\omega t\). The magnitude of displacement current through the capacitor is:
(the plate Area = \(A\), separation of plates = \(d\))
1. \(q_{0}\cos \left(\omega t \right)\)
2. \(q_{0} \omega \sin\omega t\)
3. \(q_{0} \omega \cos \omega t\)
4. \(\frac{q_{0} A \omega}{d} \cos \omega t\)

The rate of change of the voltage of a parallel plate capacitor if the instantaneous displacement current of 1 A is established between the two plates of a 1 $\mu$F parallel plate capacitor:

1. ${10}^6 V/s$

2. 10 V/s

3. ${10}^8 V/s$ 

4. ${10}^{-6} V/s$

The relation between electric field E and magnetic field induction B in electromagnetic waves is given by:

(1) $E=\sqrt{\frac{{\mu }_0}{{\epsilon }_0}} B$

(2) E = cB

(3) E = $\frac{B}{c}$

(4) $E=\frac{B}{c^2}$

In a plane EM wave, the electric field oscillates sinusoidally at a frequency of \(2.5\times 10^{10}~\text{Hz}\) and amplitude \(480\) V/m.  The amplitude of the oscillating magnetic field will be:
1. \(1.52\times10^{-8}~\text{Wb/m}^2\)
2. \(1.52\times10^{-7}~\text{Wb/m}^2\)
3. \(1.6\times10^{-6}~\text{Wb/m}^2\)
4. \(1.6\times10^{-7}~\text{Wb/m}^2\)

The intensity of visible radiation at a distance of \(1\) m from a bulb of \(100\) W which converts only \(5\%\) of its power into light, is:
1. \(0.4\) W/m²
2. \(0.5\) W/m²
3. \(0.1\) W/m²
4. \(0.01\) W/m²

On an EM wave, the amplitude of electric and magnetic fields are 100 v/m and 0.265 A/m.  The maximum energy flow is

(1) 26.5 $W/m^2$           (2) 46.7 $W/m^2$

(3) 66.5 $W/m^2$            (4) 86.5 $W/m^2$

The most penetrating radiation out of the following is: 

(1) X-rays        (2) $\beta$-rays            (3) $\alpha$-rays           (4) $\gamma$-rays

The magnetic field in a plane EM wave traveling in the positive x-direction is given by 

$\mathrm{B}=\left(100\mathrm{\mu T}\right) \sin \left[\right(2\times {10}^{15}{\mathrm{s}}^{-1}\left)\right(\mathrm{t}-\mathrm{x}/\mathrm{c}\left)\right]\hat{\mathrm{j}}$

The equation for electric field is :

1. E=100sin [(2$\times {10}^{15}{s}^{-1})$(t-x/c)]$\left(-\hat{k}\right)$

2. E=(3$\times {10}^{10} \mu V/m$)sin [(2$\times {10}^{15}{s}^{-1})$(t-x/c)]$\left(-\hat{k}\right)$

3. E=3$\times {10}^{10}$sin [(2$\times {10}^{15}{s}^{-1})$(t-x/c)] $\hat{k}$

4. E=100sin [(2$\times {10}^{15}{s}^{-1})$(t-x/c)] $\hat{k}$

Statement I: A changing electric field produces a magnetic field.

Statement II: A changing magnetic field produces an electric field.

(1) If both statement-I and Statement-II are true, and Statement-II is the correct explanation of Statement-I.

(2) If both Statement-I and Statement-II are true but Statement-II is not the correct explanation of Statement-I.

(3) If Statement-I is true but Statement-II is false.

(4) If Statement-I is false but Statement-II is true.