Q. No.Lack of independent assortment between two genes A and B would be due to
1. Crossing over
2. Linkage
3. Repulsion
4. Recombination.
1. Crossing over
2. Linkage
3. Repulsion
4. Recombination.
Recessive gene present on one X- chromosome of humans will be
1. Lethal
2. Sublethal
3. Expressed in males
4. Expressed in females.
Genotype of hybrid is known by crossing
1. F2 progeny with female parent
2. F1 × F1
3. Crossing F1 with recessive parent
4. F2 with recessive parent.
In pea, yellow seed colour is dominant over green colour. Heterozygous yellow seeded plant is crossed with green seeded plant. The ratio of yellow & green seeded offspring will be
1. 9 : 1
2. 1 : 3
3. 3 : 1
4.50 : 50
A human male produces diallelic sperms in equal proportion AB, Ab, aB, and ab. The genotype of the person would be:
| 1. | Aa Bb | 2. | Aa BB |
| 3. | AA Bb | 4. | AA BB. |
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Which one of the following conditions in humans is correctly matched with its chromosomal abnormality/linkage ?
1. Erythroblastosisfetalis – X- linked
2. Down’s syndrome – 44 autosomes + XO
3. Klinefelter’ssyndrome – 44 autosomes + XXY
4. Colour blindness – Y-linked
The most popularly known blood grouping is the ABO grouping. It is named ABO and not ABC, because “O” in it refers to having:
| 1. | No anitgens A and B on RBCs |
| 2. | Other antigens besides A and B on RBCs |
| 3. | Overdominance of this type on the genes for A and B types |
| 4. | One antibody only - either anti-A or anti-B on the RBCs |
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Study the pedigree chart given below:
What does it show:
| 1. | Inheritance of a recessive sex-linked disease like haemophilia |
| 2. | Inheritance of a sex-linked inborn error of metabolism like phenylketonuria |
| 3. | Inheritance of condition like phenylketonuria as an autosomal recessive trait |
| 4. | The pedigree chart is wrong as this is not possible |
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Which one of the following symbols and its representation, used in human pedigree analysis is correct?
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