Griffith co-injected the heat-killed S and live R strains of Pneumococcus bacterium into the mice and much to his surprise the mice developed pneumonia and died. He concluded that:

I: Live R was transformed into Live S strain as he was able to isolate Live S strain from the blood of the infected mice.
II: Bacterial transformation is a stable and heritable change as the culture of bacteria isolated from dead mice was unable to infect other mice.
 
1. Both I and II are correct
2. Only I is correct
3. Only II is correct
4. Both I and II are incorrect

Subtopic:  Search for Genetic Material |
 61%
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The radius of the double helix of B-DNA [Watson and Crick model] is approximately:

1.1.0 nm2.2.0 nm
3.0.34 nm4.3.4 nm

Subtopic:  DNA Double Helix |
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An RNA primer is essential for DNA synthesis carried out by DNA polymerase III. This is because, to synthesize DNA, DNA polymerase III requires:

1.  A free 3’ – PO4 group
2.  A free 5’ – PO4 group
3.  A free 3’ – OH group
4.  A free 5’ – OH group

Subtopic:  DNA Replication |
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Which of the following possible modes of replication was eliminated by Meselson and Stahl based on the finding after one generation of replication of the bacterium?

1. Dispersive 2. Semi-conservative
3. Conservative 4. Both 1 and 3

Subtopic:  Search for Genetic Material |
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The mRNA codon GUG codes for:

1. Valine 2. Glutamic acid
3. Tryptophan 4. Formylated methionine
Subtopic:  Translation |
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What defines the template and coding strand of DNA for transcription?
1. Presence of the structural gene in a transcription unit

2. The core RNA polymerase enzyme

3. Presence of the promoter in a transcription unit

4. Presence of 3’ – 5’ TAC codon on the DNA template

Subtopic:  Transcription: I |
 75%
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In eukaryotes, RNA polymerase III transcribes:

1. hnRNA, snRNAs and 5.8S RNA
2. tRNA, 5.8S RNA and snRNAs
3. tRNA, 5SrRNA and snRNAs
4. rRNAs – 28S, 18S and 5S

Subtopic:  Transcription: I |
 72%
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Identify the incorrect statement:

1. The DNA of the bacteriophage  ϕ X 174 has 5386 nucleotides.
2. Bacteriophage lambda DNA has 48502 base pairs.
3. The DNA of Escherichia coli has 4.6 X 103 base pairs.
4. Haploid content of human DNA is 3.3 X 109 base pairs.
Subtopic:  The DNA |
 85%
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In a DNA strand, two nucleotides are linked through a ___________ linkage to form a dinucleotide.

1. 3’ – 5’ phosphodiester bond

2. 5’ – 3’ phosphodiester bond

3. 1’ N-glycosidic bond

4. Two or three hydrogen bonds

Subtopic:  DNA Double Helix |
 62%
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The bacterial promotor sequence usually found at the -10 position (ten base pairs upstream of the transcription start site) is:
1. TTGACA
2. TAGACA
3. TATAAT
4. TATTAT

Subtopic:  Transcription: I |
 81%
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