Mark the reaction among the following that does not give benzoic acid as the major product:

1.
2.
3.
4.

The vapor of secondary alcohol passed over heated copper at 573 K yield:

The major products C and D formed in the following reaction respectively are:
\(CH_3CH_2CH_2OC{(CH_3)}_3 \xrightarrow[\Delta]{\text{Excess}\ HI}\ C + D\)

1. ${\mathrm{}}_{}$H₃C-CH₂-CH₂-I  and I-C(CH₃)₃

2. H₃C-CH₂-CH₂-OH  and I-C(CH₃)₃

3. H₃C-CH₂-CH₂-I  and HO-C(CH₃)₃

4. H₃C-CH₂-CH₂-OH  and HO-C(CH₃)₃

The structure of intermediate A in the following reaction is:

1.		2.
3.		4.

 CH₃ — O — CH(CH₃)₂ + HI → B (Product)

The product 'B' in the above mentioned reaction is-

1. CH₃OH + (CH₃)₂CHl

2. lCH₂OCH(CH₃)₂

3. CH₃OC(CH₃)₂

4. CH₃l + (CH₃)₂CHOH

The compound on hydrolysis of 50% aqueous sodium hydroxide that produces the corresponding alcohol and acid is:

1. $C_6{H}_{5}C{H}_{2}CHO$

2. $C_6{H}_{5}CHO$

3. $C{H}_{3}C{H}_{2}C{H}_{2}CHO$

4. ${\mathrm{CH}}_3-\stackrel{\mathrm{O}}{\stackrel{\left|\right|}{\mathrm{C}}}-{\mathrm{CH}}_3$

The product 'Z' in the below-mentioned reaction is:

1. $C{H}_2=C{H}_2$

2. $C{H}_{3}C{H}_2-O-C{H}_2-C{H}_3$

3. $C{H}_3-C{H}_2-O-S{O}_{3}H$

4. $C{H}_{3}C{H}_{2}OH$

H₂COH.CH₂OH on heating with per-iodic acid gives:

1. 2CO₂

2. 2 HCOOH

3.  

 

4. 

Phenol in a set of reactions (as captured below) yielded a product Z.

\(\text{Phenol}\ \xrightarrow{\text{Zn Dust}}\ \text{X}\ \xrightarrow[\text{Anhy. }{AlCl_3}]{CH_3Cl}\ Y\)
\( Y\ \xrightarrow[KMnO_4]{\text{Alkaline}}\ Z\)
The structure of the product Z would be:

The product 'D' in the above-mentioned reaction is: 

1.		2.
3.		4.