In the reaction with HCl, an alkene reacts in accordance with Markovnikov's rule, to give a product 1-chloro-1-methylcyclohexane. The possible alkene is:

1. 2.

3. (1) and (2) 4.

Subtopic: Alkanes, Alkenes and Alkynes - Chemical Properties |

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Q48:

Consider the nitration of benzene using mixed conc. H₂SO₄ and HNO₃. If a large amount of KHSO₄ is added to the mixture, the rate of nitration will be

1. slower
2. unchanged
3. doubled
4. faster

Subtopic: Common Ion Effect |

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Q49:

In the reaction,

H - C \equiv CH \to_{(ii) {CH}_{3} {CH}_{2} Br}^{(i) {NaNH}_{2} / liq . {NH}_{3}} X \to_{(ii) {CH}_{3} {CH}_{2} Br}^{(i) {NaNH}_{2} / liq . {NH}_{3}} Y

X and Y are:

1. X = 2 –Butyne; Y = 3 –Hexyne
2. X = 2 – Butyne; Y = 2-Hexyne
3. X = 1-Butyne; Y = 2-Hexyne
4. X = 1 – Butyne; Y = 3 – Hexyne

Subtopic: Alkanes, Alkenes and Alkynes - Chemical Properties |

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Q50:

The compound

C_{7} H_{8}

undergoes the following reactions :

C_{7} H_{8} \overset{3 {Cl}_{2} / ∆}{\to} A \overset{{Br}_{2} / Fe}{\to} B \overset{Zn / HCl}{\to}

C
The product 'C' is

1. m–Bromotoluene
2. o–Bromotoluene
3. 3–Bromo–2,4,6–trichlorotoluene
4. p–Bromotoluene

Subtopic: Aromatic Hydrocarbons - Benzene - Structure, Preparation & Chemical Reactions |

NEET - 2018

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Q51:

Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is

1.

CH \equiv CH

2.

{CH}_{2} = {CH}_{2}

3.

{CH}_{3} - {CH}_{3}

4.

{CH}_{4}

Subtopic: Alkanes, Alkenes and Alkynes - Chemical Properties |

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Q52:

The compound that will react most readily with gaseous bromine has the formula is-

1. $C_{3} H_{6}$

2. $C_{2} H_{2}$

3. $C_{4} H_{10}$

4. $C_{2} H_{4}$

Subtopic: Alkanes, Alkenes and Alkynes - Chemical Properties |

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Q53:

In the given reaction:

The product P is:

1.		2.
3.		4.

Subtopic: Alkanes, Alkenes and Alkynes - Chemical Properties |

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Q54:

In which of the following molecules, all atoms are coplanar?

1.

2.

3.

4.

Subtopic: Hybridisation |

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Q55:

Which of the following can be used as the halide component for Friedel-Crafts reaction?

1. Chlorobenzene

2. Bromobenzene

3. Chloroethene

4. Isopropyl chloride

Subtopic: Aromatic Hydrocarbons - Benzene - Structure, Preparation & Chemical Reactions |

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Q56:

Predict the correct intermediate and product in the following reaction:

H_{3} C - C \equiv CH \to_{{HgSO}_{4}}^{H_{2} O, H_{2} {SO}_{4}} \underset{(A)}{Intermediate} \to \underset{(B)}{Product}

1.

A : H_{3} C - \underset{OH}{\underset{|}{C}} = {CH}_{2}; B : H_{3} C - \underset{{SO}_{4}}{\underset{|}{C}} = {CH}_{2}

2.

A : H_{3} C - \underset{O}{\underset{| |}{C}} - {CH}_{3}; B : H_{3} C - C \equiv CH

3.

A : H_{3} C - \overset{OH}{\overset{|}{C}} = {CH}_{2}; B : H_{3} C - \overset{O}{\overset{| |}{C}} - {CH}_{3}

4.

A : H_{3} C - \underset{S O_{4}}{\underset{|}{C}} = {CH}_{2}; B : H_{3} C - \underset{O}{\underset{| |}{C}} - {CH}_{3}

Subtopic: Alkanes, Alkenes and Alkynes - Chemical Properties |

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In the reaction with HCl, an alkene reacts in accordance with Markovnikov's rule, to give a product 1-chloro-1-methylcyclohexane. The possible alkene is:

1. 2.

3. (1) and (2) 4.

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In the reaction with HCl, an alkene reacts in accordance with Markovnikov's rule, to give a product 1-chloro-1-methylcyclohexane. The possible alkene is:

1. 2.

3. (1) and (2) 4.