In the following reaction, the product (A) 
+  is :

 

1. 

 

2. 

 

3. 

 

4. 

 

Method by which aniline cannot be prepared is

1. Hydrolysis phenyl isocyanide with acidic solution

2. Degradation of benzamide with bromine in alkaline Solution

3. Reduction of nitrobenzene with H/Pd in ethanol

4. Potassium salt of phthalimide treated with chlorobenzene followed by the hydrolysis aqueous NaOH solution

A given nitrogen-containing aromatic compound A reacts with Sn/HCl, followed by HNO₂ to give an unstable compound B. B, on treatment with phenol, forms a beautiful coloured compound C with the molecular formula C₁₂H₁₀N₂O . The structure of compound A is-

1.  

2.  

3.  

4.  

Which one of the following nitro-compounds does not react with nitrous acid

1.  

2.  

3.  

4.  

Nitration of aniline in strong acidic medium also gives m-nitroaniline because

1. In spite of substituents nitro group always goes to only m-position

2. In electrophilic substitution reactions amino group is meta directive

3. In absence of substituents nitro group always goes to only m-position

4. In acidic (strong) medium aniline is present as anilinium ion

An aromatic amine (A) was treated with alcoholic potash and another compound (Y) when a foul smelling gas was formed with formula C₆H₅NC. (Y) was formed by reacting a compound (Z) with Cl₂ in the presence of slaked lime. Compound (Z) is:

1. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2$

2. ${\mathrm{CH}}_3\mathrm{OH}$

3. ${\mathrm{CH}}_3{\mathrm{COCH}}_3$

4. ${\mathrm{CHCl}}_3$

The correct order of basicities of the following compounds is:

$\underset{1}{{\mathrm{CH}}_3-\underset{{\mathrm{NH}}_2}{\overset{\mathrm{NH}}{\underset{\left|\right|}{\overset{\left|\right|}{\mathrm{C}}}}}}, \underset{2}{C{H}_{3}C{H}_{2}N{H}_2} , \underset{3}{{\left(C{H}_3\right)}_{2}NH} , \underset{4}{ C{H}_3-\stackrel{O}{\stackrel{\left|\right|}{C}}-N{H}_2}$

1. 2 > 1 > 3 > 4

2. 1> 3 > 2 > 4

3. 3 > 1 > 2 > 4

4. 1 > 2 > 3 > 4