Q. No.In an electrical cable, there is a single wire of radius 9 mm of copper. Its resistance is 5 Ω. The cable is replaced by 6 different insulated copper wires, the radius of each wire is 3 mm. Now the total resistance of the cable will be :
(1) 7.5 Ω
(2) 45 Ω
(3) 90 Ω
(4) 270 Ω
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A wire of resistance R is cut into ‘n’ equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be :
(1) nR
(2)
(3)
(4)
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If each resistance in the figure is of 9 Ω then reading of ammeter is
(1) 5 A
(2) 8 A
(3) 2 A
(4) 9 A
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The length of a given cylindrical wire is increased by 100%. Due to the consequent decrease in diameter, the change in the resistance of the wire will be :
(1) 300%
(2) 200%
(3) 100%
(4) 50%
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The potential difference across 8 ohms resistance is 48 volts as shown in the figure. The value of potential difference across X and Y points will be :
(1) 160 volt
(2) 128 volt
(3) 80 volt
(4) 62 volt
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A, B, and C are voltmeters of resistance R, 1.5R, and 3R respectively as shown in the figure. When some potential difference is applied between X and Y, the voltmeter readings are VA, VB, and VC respectively. Then,
1. VA=VB=VC
2. VA≠VB=VC
3. VA=VB≠VC
4. VA≠VB≠VC
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A metallic block has no potential difference applied across it, then the mean velocity of free electron is (T = absolute temperature of the block) :
(1) Proportional to T
(2) Proportional to
(3) Zero
(4) Finite but independent of temperature
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If in the circuit shown below, the internal resistance of the battery is 1.5 Ω and VP and VQ are the potentials at P and Q respectively, what is the potential difference between the points P and Q
(1) Zero
(2) 4 volts (VP > VQ)
(3) 4 volts (VQ > VP)
(4) 2.5 volts (VQ > VP)
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In the circuit in the figure, if the potential at point A is taken to be zero, the potential at point B is :
1. -1V 2. +2V
3. -2V 4. +1V
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