An AC voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3, the phase difference between the applied voltage and the current in the circuit is:
1.
2.
3. zero
4.
In the given circuit the reading of voltmeter V1 and V2 are 300 V each. The reading to the voltmeter V3 and ammeter A are respectively:
1. 150 V, 2.2 A
2. 220 V, 2.2 A
3. 220 V, 2.0 A
4. 100 V, 2.0 A
An inductor 20 mH, a capacitor 100 μF, and a resistor 50 are connected in series across a source of emf, V= 10sin314t. The power loss in the circuit is:
1. 0.79 W
2. 0.43 W
3. 2.74 W
4. 1.13 W
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The potential differences across the resistance, capacitance and inductance are 80 V, 40 V and 100 V respectively in an L-C-R circuit. The power factor of this circuit is:
1. 0.4
2. 0.5
3. 0.8
4. 1.0
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1. | \(\frac{\varepsilon^{2} R}{\left[R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}\right]}\) | 2. | \(\frac{\varepsilon^{2} \sqrt{R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}}}{R}\) |
3. | \(\frac{\varepsilon^{2}\left[R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}\right]}{R}\) | 4. | \(\frac{\varepsilon^{2}R}{\sqrt{R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}}}\) |
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The figure shows a circuit that contains three identical resistors with resistance R = 9.0 each, two identical inductors with inductance L = 2.0 mH each, and an ideal battery with emf . The current 'i' through the battery just after the switch closed is:
1. 0.2A
2. 2A
3. 4 A
4. 2mA
A coil of inductive reactance of \(31~\Omega\) has a resistance of \(8~\Omega\). It is placed in series with a condenser of capacitive reactance \(25~\Omega\). The combination is connected to an AC source of \(110\) V. The power factor of the circuit is:
1. \(0.56\)
2. \(0.64\)
3. \(0.80\)
4. \(0.33\)
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