A concave lens of glass of refractive index 1.5 has both surfaces of the same radius of curvature R. On immersion in a medium of refractive index 1.75, it will have as a

1. Divergent lens of focal length 3R

2. Divergent lens of focal length 4R

3. Convergent lens of focal length 3.5R

4. Convergent lens of focal length 5R

A ray is incident normally on a right-angled prism whose R.I is $\sqrt{3}$ and prism angle $\mathrm{A}=30°$. Deviation to the ray is equal to

(1) $\frac{\mathrm{\pi }}{2}$

(2) $\frac{\mathrm{\pi }}{6}$

(3) $\frac{3\mathrm{\pi }}{2}$

(4) 2$\mathrm{\pi }$

A convex lens forms the image of a point object \(O\) on the screen. If a glass slab of thickness 3 cm and refractive index 1.5 is put as shown below, then to have the image of the object on the screen, the object should be shifted:

Two convex lenses of focal lengths $f_1 and f_2$ are separated co-axially by a distance d. The power of the combination will be zero if d equals to

1. $\sqrt{f_1{f}_2}$

2. $f_1+f_2$

3. $\frac{f_1-f_2}{2}$

4. $\frac{f_1+f_2}{2}$

In the following diagram what is the distance x if the radius of curvature R=15 cm?

(1) 30 cm

(2) 20 cm

(3) 15 cm

(4) 10 cm

A thin equiconvex lens of power P is cut into three parts A, B, and C as shown in the figure. If $P_1, P_2 \mathrm{and} P_3$ are powers of the three parts respectively, then 

1.  $P_1 = P_2 = P_3$

2.  $P_1 > P_2 = P_3$

3.  $P_1 < P_2 = P_3$

4.  $P_2 = P_3 = 2P_1$

In the diagram shown below, the image of the point object O is formed at l by the convex lens of focal length 20 cm, where $F_1 and F_2$ are foci of the lens. The value of x' is

(1) 10 cm

(2) 20 cm

(3) 30 cm

(4) 40 cm

An astronomical telescope has angular magnification of \(40\) in its normal adjustment. If focal length of eyepiece is \(5\) cm, the length of the telescope is:
1. \(190\) cm
2. \(200\) cm
3. \(205\) cm
4. \(210\) cm

In case of refraction through a glass slab, if i is very small, the lateral shift is (t is thickness, u is the refractive index)

1. $t\left(1+\frac{1}{\mu }\right)i$

2. $t\left(1-\frac{1}{\mu }\right)i$

3. $t\left(2+\frac{1}{\mu }\right)i$

4. $t\left(2-\frac{1}{\mu }\right)i$

The angle of a distant object formed at the objective of a telescope is 2 minutes. If the focal length of objective and eyepiece of the telescope is 200 cm and 20 cm, then the size of the image formed by the objective is approximately

1.  20 cm

2.  0.12 cm

3.  0.4 cm

4.  12 cm