Four-point +ve charges of the same magnitude (Q) are placed at four corners of a rigid square frame as shown in the figure. The plane of the frame is perpendicular to Z-axis. If a –ve point charge is placed at a distance z away from the above frame (z<<L) then 

(1) – ve charge oscillates along the Z-axis.

(2) It moves away from the frame

(3) It moves slowly towards the frame and stays in the plane of the frame

(4) It passes through the frame only once.

Subtopic:  Coulomb's Law |
 63%
From NCERT
AIIMS - 2005
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A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux for the surface of the cylinder is given by 

(1) 2πR2E

(2) πR2/E

(3) (πR2πR)/E 

(4) Zero

Subtopic:  Gauss's Law |
 74%
From NCERT
PMT - 1975
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An electric charge is placed at the centre of a cube of side α. The electric flux on one of its faces will be 

(1) q6ε0

(2) qε0a2

(3) q4πε0a2

(4) qε0 

Subtopic:  Electric Field | Gauss's Law |
 91%
From NCERT
AIIMS - 2001
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Total electric flux coming out of a unit positive charge put in air is 

(1) ε0

(2) ε01

(3) (4pε0)1

(4) 4πε0 

Subtopic:  Gauss's Law |
 83%
From NCERT
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A cube of side l is placed in a uniform field E, where E=Ei^. The net electric flux through the cube is

(1) Zero

(2) l2E

(3) 4l2E

(4) 6l2E

Subtopic:  Gauss's Law |
 76%
From NCERT
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Shown below is a distribution of charges. The flux of electric field due to these charges through the surface S is 

(1) 3q/ε0

(2) 2q/ε0

(3) q/ε0 

(4) Zero

Subtopic:  Gauss's Law |
 87%
From NCERT
AIIMS - 2003
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The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q1 = –14 nC, q2 = 78.85 nC, q3 = – 56 nC) 

(1) 103 Nm2 C–1

(2) 103 CN-1 m–2

(3) 6.32 × 103 Nm2 C–1

(4) 6.32 × 103 CN-1 m–2

Subtopic:  Gauss's Law |
 60%
From NCERT
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The electric intensity due to an infinite cylinder of radius R and having charge q per unit length at a distance r(r > R) from its axis is 

(1) Directly proportional to r2

(2) Directly proportional to r3

(3) Inversely proportional to r

(4) Inversely proportional to r2

Subtopic:  Electric Field |
 64%
From NCERT
PMT - 1993
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A positively charged ball hangs from a silk thread. We put a positive test charge q0 at a point and measure F/q0, then it can be predicted that the electric field strength E 

(1) > F/q0

(2) = F/q0

(3) < F/q0

(4) Cannot be estimated

Subtopic:  Electric Field |
From NCERT
PMT - 1990
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The charge on \(500~\text{cc}\) of water due to protons will be: 

1. \(6.0\times 10^{27}~\text{C}\) 2. \(2.67\times 10^{7}~\text{C}\)
3. \(6\times 10^{23}~\text{C}\) 4. \(1.67\times 10^{23}~\text{C}\)
Subtopic:  Electric Charge |
 59%
From NCERT
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