A cyclic process ABCA is shown in the V-T diagram. Process on the P-V diagram is -

(1)

(2)

(3)

(4)

Heat energy absorbed by a system in going through a cyclic process shown in figure is 

(1) 10⁷ π J

(2) 10⁴ π J

(3) 10²π J

(4) 10^–3π J

A thermodynamic system is taken from state A to B along ACB and is brought back to A along BDA as shown in the PV diagram. The net work done during the complete cycle is given by the area

(1) P₁ACBP₂P₁

(2) ACBB'A'A

(3) ACBDA

(4) ADBB'A'A

The P-V graph of an ideal gas cycle is shown here as below. The adiabatic process is described by

(1) AB and BC

(2) AB and CD

(3) BC and DA

(4) BC and CD

An ideal monoatomic gas is taken round the cycle  as shown in following P-V diagram. The work done during the cycle is -

(1) PV

(2) 2 PV

(3) 4 PV

(4) Zero

A system changes from the state (P₁, V₁) to (P₂, V₂) as shown in the figure. What is the work done by the system ?

(1) 7.5 × 10⁵ joule

(2) 7.5 × 10⁵ erg

(3) 12 × 10⁵ joule

(4) 6 × 10⁵ joule

Carbon monoxide is carried around a closed cycle abc in which bc is an isothermal process as shown in the figure. The gas absorbs 7000 J of heat as its temperature increases from 300 K to 1000 K in going from a to b. The quantity of heat rejected by the gas during the process ca is -

(1) 4200 J

(2) 5000 J

(3) 9000 J

(4) 9800 J

When a system is taken from state i to a state f along path iaf, Q = 50 J and W = 20 J. Along path ibf, Q = 35 J. If W = –13 J for the curved return path f i, Q for this path is

(1) 33 J

(2) 23 J

(3) – 7 J

(4) – 43 J

An ideal gas is taken from point A to point B, as shown in the P-V diagram. The work done in the process is:

       
1. $(P_A-P_B)(V_B-V_A)$
2. $\frac{1}{2}(P_B-P_A)(V_B+V_A)$
3. $\frac{1}{2}(P_B-P_A)(V_B-V_A)$
4. $\frac{1}{2}(P_B+P_A)(V_B-V_A)$

Consider a process shown in the figure. During this process the work done by the system -

(1) Continuously increases

(2) Continuously decreases

(3) First increases, then decreases

(4) First decreases, then increases