Both CN- and N2 isoelectronic but in contrast to CN- , N2 is chemically inert due to

1.  Unsymmetrical electron distribution

2.  Low bond energy

3.  The pressure of a greater number of electrons in bonding orbitals

4.  Absence of bond polarity

Subtopic:  Octate, Isoelectronic Species, Lewis Structure & Formal Charge |
 63%
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In P4 (Tetrahedral) molecule

1.  Each P is joined to four P

2.  Each P is joined to three P

3.  Each P is joined to two P

4.  P4 does not exist

Subtopic:  Covalent Bond |
 62%
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molecular shapes of SF4, CF4 and XeF4 are 

1.  Same with 2, 0 and 1 lone pairs of electrons respectively

2.  The same with 1, 1 and 1 lone pairs of electrons respectively 

3.  Different with 0, 1 and 2 lone pairs of electrons respectively 

4.  Different with 1, 0 and 2 lone pairs of electrons respectively

 

Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
 88%
From NCERT
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Correct regarding edges and faces in lF7 respectively 

1.  15, 10

2.  10, 10

3.  7, 15

4.  15, 7

Subtopic:  Introduction & Crystal System |
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Electronegativity of A and B is 1 and 4 respectively. The percentage of the covalent character of AB is

1.  79.5%

2.  8%

3.  20.5%

4.  25%

Subtopic:  Polarity |
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The bond energies in NO, NO+ and NO- follow the order

1.  NO+ > NO > NO-

2.  NO > NO+ > NO-

3.  NO- > NO > NO+

4.  NO+ > NO- > NO

Subtopic:  M.O.T |
 76%
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The element which readily forms an ionic bond has the electronic configuration

1. 1s22s22p3

2. 1s22s22p1

3. 1s22s22p2

4.1s22s22p63s1

Subtopic:  Ionic Bond |
 79%
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The correct of FX^F bond angle (X = central atom) in CF4, POF3 and SO2F2 is

1.  SO2F2 < POF3 < CF4

2.  POF3 < CF4< SO2F2 

3.   CF4 < SO2F2 < POF3

4.  POF3 < SO2F2 < CF4

Subtopic:  V.S.E.P.R & V.B.T |
 57%
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In the cyanide ion, the negative charge is on 

1.  C

2.  N

3.  Both C and N

4.  Resonate between C and N

Subtopic:  Types of Chemical Bond |
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