Acetylene reacts with 42% ${\mathrm{H}}_2{\mathrm{SO}}_4$ containing 1% ${\mathrm{HgSO}}_4$ to give:

1. ${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{HSO}}_4$                               2. ${\mathrm{CH}}_3\mathrm{CHO}$

3. HCHO                                       4. ${\mathrm{CH}}_2={\mathrm{CH}}_2$

When ${\mathrm{CaC}}_2$ was hydrolysed a gas was obtained. It had a garlic odour due to phosgene present as impurity. The gas was passed through ammoniacal solution of ${\mathrm{Cu}}_2{\mathrm{Cl}}_2$, a red ppt. was obtained. The gas was:

1. ethylene                                       2. propyne

3. acetylene                                      4. ethane

Ozonolysis (${\mathrm{O}}_3$, ${\mathrm{H}}_2{\mathrm{O}}_2$) of, ${\mathrm{CH}}_3-\underset{{\mathrm{CH}}_3}{\underset{|}{\mathrm{CH}}}-\mathrm{C}\equiv \mathrm{C}-{\mathrm{CH}}_3$ gives :

1.  ${\mathrm{CH}}_3\underset{{\mathrm{CH}}_3}{\underset{|}{\mathrm{CH}}}\mathrm{COOH}$+ ${\mathrm{CH}}_3\mathrm{COOH}$

2. ${\mathrm{CH}}_3\underset{{\mathrm{CH}}_3}{\underset{|}{\mathrm{CH}}}\mathrm{CHO}$ + ${\mathrm{CH}}_3\mathrm{CHO}$

3. ${\mathrm{CH}}_3\underset{{\mathrm{CH}}_3}{\underset{|}{\mathrm{CH}}}\mathrm{CHO}$ + ${\mathrm{CH}}_3\mathrm{COOH}$

4. none of the above

$\hspace{0.17em}\mathrm{R}-{\mathrm{CH}}_2-{\mathrm{CCl}}_2-\mathrm{R}\stackrel{\mathrm{Reagent}}{\to }$$\mathrm{R}-\mathrm{C}\equiv \mathrm{C}-\mathrm{R}$. The reagent is

1. Na                                     2. HCl in ${\mathrm{H}}_2\mathrm{O}$

3. KOH in ${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}$                 4. Zn in alcohol 

The reaction,

$\stackrel{{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }$ is the example of:

(a) sulphonation                            (b) dehydration

(c) alkylation                                 (d) decomposition

The end product 'W' in the follownign sequence of reactions is :

1.		2.
3.	\(Ph-CH_2-O-CH_2-CH_2-Ph\)	4.

Consider the following reaction sequence

$\stackrel{{\mathrm{HNO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4}{\to } \stackrel{Sn+HCl}{\to }\underset{\left(6H\right)}{\overset{NaN{O}_2+HCl}{\to }}\stackrel{C{u}_2{\left(CN\right)}_2+HCN}{\to }\stackrel{H_{2}O}{\to }Product$

Product is

(1)
(2)
(3)
(4)

${\mathrm{CH}}_3\mathrm{Cl} \stackrel{ }{\to }{\mathrm{CH}}_4$

Above conversion can be achieved by:

(a) Zn/H⁺

(b) LiAlH₄

(c) Mg /(ether) then H₂O

(d) all of these

CH₃-CH₂-CH₂-CH₃    $\stackrel{AlCl3/∆}{\to }$         CH₃-CH-CH₃
                                                                       l
                                                                       CH3

Above reaction is an example of:-
(a)isomerization (b)polymerization (c)cracking (d)de-hydrogenation

 (Kolbe electrolysis method)

Product (A) of the reaction is :

1. CH₃-CH₃

2. CH₂=CH2

3. CH₃-CH=CH₂

4. none of these