Which of the following compounds will give isocyanide test with ${\mathrm{CHCl}}_3/\mathrm{KOH}$?

1.  

2.  

3.  

4.  

Give the incorrect order of basic strength

1.  ${\mathrm{PhNH}}_2<\mathrm{PhNHMe}<{\mathrm{PhNMe}}_2$

2.  $\mathrm{p}-{\mathrm{CH}}_3{\mathrm{PhNH}}_2>\mathrm{m}-{\mathrm{CH}}_3{\mathrm{PhNH}}_2>{\mathrm{PhNH}}_2>\mathrm{o}-{\mathrm{CH}}_3{\mathrm{PhNH}}_2$

3.  ${\mathrm{PhNH}}_2>\mathrm{m}-{\mathrm{NO}}_2{\mathrm{PhNH}}_2>\mathrm{p}-{\mathrm{NO}}_2{\mathrm{PhNH}}_2>\mathrm{O}-{\mathrm{NO}}_2{\mathrm{PhNH}}_2$

4.  $\mathrm{o}-{\mathrm{CH}}_3{\mathrm{OPhNH}}_2>\mathrm{p}-{\mathrm{CH}}_3{\mathrm{OPHNH}}_2>{\mathrm{PhNH}}_2>\mathrm{m}-{\mathrm{CH}}_3{\mathrm{OPhNH}}_2$

For the following reaction

(major product) will be

1.  

2.  

3.  

4.  

Which of the following substituent as 'X' not decreases the rate of reaction with respect to aniline?

1.  

2.  $-{\mathrm{CH}}_3$

3.  $-{\mathrm{NO}}_2$

4.  -CHO

Identify the major product (A) formed in the following reaction/\.

1.               2.  

3.        4.  

Which of the following compounds will not give Hoffmann bromamide reaction?
 

1.
2.
3.
4.

1.           

2.  

3.       

4.  

Which of the following is more basic than aniline ?

1. Diphenylamine

2. Triphenylamine

3. p-nitroaniline

4. Benzylamine

Which of the following will be most stable diazonium salt $R{\mathrm{N}}_2^{+}{X}^{-}$ ?

(a) ${\mathrm{CH}}_3{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

(b) ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

(c) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{N}}_2^{+}{\mathrm{X}}^{-}$

(d) ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2{\mathrm{N}}_2^{+}{X}^{-}$

The correct statement regarding the basicity of arylamines is

(1) Arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalized by interaction with the aromatic ring p-electron system.

(2) Arylamines are generally more basic than alkylamines because of aryl group.

(3) Arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridized

(4) Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring p-electron system.

A given nitrogen-containing aromatic compound a reacts with Sn/HCl, followed by HNO₂ to give an unsatable compound B.B, on treament with phenol, forms a beautiful coloured compound C with the molecular formula C₁₂H₁₀N₂O. The structure of compound A is