A uniform rod of mass m and length L pivoted from its one end is executing SHM with time period T. If rod suddenly breaks from the middle while passing through its mean position, then the time period of oscillation of remaining half part will be

1.  2T

2.  T2

3.  2T

4.  T2

Subtopic:  Angular SHM |
 66%
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A pendulum oscillates about its mean position \(\mathrm{C}.\) The position where the speed of the bob becomes maximum is: (ignore all dissipative forces)

                  

1. \(\mathrm{A}\) 2. \(\mathrm{B}\)
3. \(\mathrm{C}\) 4. \(\mathrm{D}\)
Subtopic:  Angular SHM |
 84%
From NCERT
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A particle executes linear SHM between \(x=A.\) The time taken to go from \(0\) to \(A/2\) is \(T_1\) and to go from \(A/2\) to \(A\) is \(T_2\) then:
1. \(T_1<T_2\) 2. \(T_1>T_2\)
3. \(T_1=T_2\) 4. \(T_1= 2T_2\)
Subtopic:  Linear SHM |
 72%
From NCERT
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The position x (in centimeter) of a simple harmonic oscillator varies with time t (in second) as x = 2cos0.5πt + π3The magnitude of the maximum acceleration of the particle in cm/s2 is:

1.  π/2

2.  π/4

3.  π2/2

4.  π2/4

Subtopic:  Simple Harmonic Motion |
 86%
From NCERT
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A horizontal platform is executing simple harmonic motion in the vertical direction with frequency f. A block of mass m is placed on the platform. What is the maximum amplitude of the SHM, so that the block is not detached from it?

1.  mg2π2f2

2.  mg4π2f2

2.  g2π2f2

4.  g4π2f2

Subtopic:  Simple Harmonic Motion |
 66%
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A body at the end of a spring executes S.H.M. with a period T1 while the corresponding period for another spring is T2. If the period of oscillation with two springs in series is T, then:

1.  T = T1 + T2

2.  T2 = T12 + T22

3.  1T = 1T1 + 1T2

4.  1T2 = 1T12 + 1T22

Subtopic:  Combination of Springs |
 63%
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A body is executing linear S.H.M. At a position x, its potential energy is E1, and at a position y, its potential energy is E2. The potential energy at the position (x + y) is

1.  E1 + E2

2.  E12 + E22

3.  E1 + E2 + 2E1E2

4.  E1E2

Subtopic:  Energy of SHM |
 59%
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The equation of a particle executing simple harmonic motion is y = 0.4 sin2πt + π3 (where t is in seconds and y is in meters). The initial phase of the particle is:

1.  2πt + π3

2.  π3

3.  7π3

4.  8π3

Subtopic:  Simple Harmonic Motion |
 82%
From NCERT
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An ideal spring-mass system has a time period of vibration T. If the spring is cut into 4 identical parts and same mass oscillates with one of these parts, then the new time period of vibration will be

1.  T2

2.  T

3.  T4

4.  2T

Subtopic:  Combination of Springs |
 71%
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The equation of a particle executing simple harmonic motion is y=22sin314t. Displacement y from the mean position where acceleration becomes zero is: (y is in cm and t is in second) 

1.  2 cm

2.  0

3.  12 cm

4.  22 cm

Subtopic:  Simple Harmonic Motion |
 75%
From NCERT
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