Following is the schematic structure of transcription unit having some important components indicated by A, B, C, D and E. In which of four option the components are identified correctly:

 

A

B

C

D

E

1.

Terminator

Transcription start site

Promoter

Template strand

Coding strand

2.

Promoter

Transcription start site

Terminator

Coding strand

Template strand

3.

Promoter

Transcription start site

Terminator

Template strand

Coding strand

4.

Terminator

Transcription start site

Promoter

Coding strand

Template strand

Subtopic:  Transcription:II | Transcription |
 79%
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The fact that the genetic code is almost universal in living organisms is considered to be evidence that all organisms:

1. Are evolutionarily related

2. Are genetically identical

3. Have the same sequence of anticodons

4. None of the above

Subtopic:  Genetic Code: III | Genetic Code |
 67%
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In the following diagram of the lac operon, an operon for inducible enzymes, identify components and enzymes:

 

X

Y

E1

E2

E3

1.

Repressor protein

Inducer (lactose)

â-Galactosidase

Permease

Transacetylase

2.

Inducer (lactose)

Repressor protein

â-Galactosidase

Permease

Transacetylase

3.

Repressor protein

Inducer (lactose)

â-Galactosidase

Transacetylase

Permease

4.

Repressor protein

Inducer (lactose)

Permease

Transacetylase

â-Galactosidase

Subtopic:  Gene Regulation: Lac Operon |
 81%
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Alfred Hershey and Martha Chase made a big contribution in proving DNA role as the hereditary molecule. The experiment is shown in the diagram. A and C are the presence or absence of radioactivity detected in cells B and D are the presence or absence of radioactivity detected in supernatants cells. Identify A, B, C and D:

1. A - No Radioactivity (35S) detected in cells; B - Radioactivity (32P) detected in supernatant; C - Radioactivity (35S) detected in cells; D - No Radioactivity in supernatant

2. A- Radioactivity (35S) detected in cells; B - No Radioactivity (35S) detected in supernatant; C - Radioactivity (32P) detected in cells; D - No Radioactivity in supernatant

3. A - No Radioactivity (35S) detected in cells; B - Radioactivity (35S) detected in supernatant; C - Radioactivity (32P) detected in cells; D - No Radioactivity in supernatant

4. A - No Radioactivity (35S) detected in cells; B - Radioactivity (35S) detected in supernatant; C - No Radioactivity (32P) detected in cells; D - Radioactivity in supernatant

Subtopic:  Search for Genetic Material: II | Search for Genetic Material |
 66%
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If the DNA of this virus was labeled with 32P and the protein of the virus was labeled with 35S, which molecule(s) would be present inside the cells?

1. 35S and 32P

2. 35S only

3. 32P only

4. Neither molecule would be present inside the cell

Subtopic:  Search for Genetic Material: II | Search for Genetic Material |
 85%
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The prediction of sequence of amino acid is _____A ____ if the sequence of nucleotides mRNA is known. The prediction of sequence of nucleotide in concerned mRNA is ____B____ because the genetic code is _____C_____:

1. A - possible, B - impossible, C - universal

2. A - possible, B - impossible, C - degenerate

3. A - impossible, B - possible, C - universal

4. A - impossible, B - possible, C - degenerate

Subtopic:  Genetic Code: III | Genetic Code |
 64%
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Choose the correct statements:

I. Binding of mRNA to the ribosome is loose and reversible.

II. The ribosome, which is composed of tRNA and proteins, consists of a small and large subunit.

III. Each of the 20 amino acids has a minimum of one specific tRNA molecule.

IV. tRNAMET binds to the first codon (AUG) - this is called the START codon.

V. The second tRNA binds to the second codon so that their attached monosaccharides are next to each other

VI. The newly formed polypeptide may undergo post-transcriptional modification.

1. I, III and IV         

2. II, IV, VI               

3. II, V and VI           

4. I, V, VI

Subtopic:  Translation Mechanism |
 56%
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If a length of DNA has 45,000 base pairs, how many complete turns will the DNA molecule take?

1. 45000  

2. 450                

3. 4500               

4. 45

Subtopic:  DNA Double Helix |
 80%
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Go through the following facts:

I. 'AAG' always code for lysine. It cannot code for any other amino acid.

II. Serine amino acid can be coded by UCU / UCC / UCA or UCG.

III. UUU from phenylalanine in bacteria as well as human beings.

IV. UUU GGG CCC AAA Me codes for five amino acids.

Now point out nature of genetic code after reading above:

1. I – Specificity / Non-ambiguity of code; II - Universality of code; III - Degeneracy of code; IV - Triplet and non-overlapping code

2. I – Specificity / Non-ambiguity of code; II - Degeneracy of code; III - Universality of code; IV - Triplet and non-overlapping code

3. I – Specificity / Non-ambiguity of code; II - Degeneracy of code; III - Universality of code; IV - Triplet and overlapping code

4. I – Specificity / Non-ambiguity of code; II - Universality of code; III - Degeneracy of code; IV - Triplet and overlapping code

Subtopic:  Genetic Code: III | Genetic Code |
 73%
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The full form of ELSI is:

1. Embedded Low Software Index    

2. Ear Lung Spleen Immunity

3. Ethical Legal and Social Issue      

4. Endonuclease Ligase Surface Immunity

Subtopic:  Human Genome Project |
 92%
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