In YDSE like an experiment, the intensity of light from both slits is the same and the interference pattern is observed along a screen parallel to the plane of ${\mathrm{S}}_{1_{}}$ and ${\mathrm{S}}_2$. If D, B, A represents the location of a minimum, a maximum, and a point where intensity is the average intensity and $\mathrm{\beta }$ is the fringe width and DB, BA, and DA represent the minimum separations, then DB, BA, and DA are:

                                     

1.  $\frac{\mathrm{\beta }}{2}, \frac{\mathrm{\beta }}{4} \mathrm{and} \frac{\mathrm{\beta }}{4}$

2. $\frac{\mathrm{\beta }}{4}, \frac{\mathrm{\beta }}{4}, \frac{\mathrm{\beta }}{2}$

3.  $\frac{\mathrm{\beta }}{2},\frac{\mathrm{\beta }}{2}, \mathrm{\beta }$

4.  $\mathrm{\beta }, \mathrm{\beta }, \frac{\mathrm{\beta }}{2}$

In Young's double-slit experiment conducted in a liquid, the 10th bright fringe in liquid lies where the 6th dark fringe lies in a vacuum. The refractive index of the liquid approximately is:

1.  1.82 

2.  1.54

3.  1.67

4.  1.20

In the optical arrangement as shown below, the axes of two polarizing sheets P and Q are oriented such that no light is detected. Now when a third polarizing sheet (R) is placed in between P and Q, then the light is detected. Which of the following statement(s) is(are) false?

1.  Polarization axes of P and Q are perpendicular to each other

2.  The polarization axis of R is not parallel to P

3.  The polarization axis of Ris not parallel to Q

4.  Polarization axes of P and Q are parallel to each other

A diffraction pattern is obtained using a beam of blue light. What happens if the blue light is replaced by red light? 

1.  No change

2.  Diffraction bands become narrower and crowded together 

3.  Bands become broader and farther apart 

4.  Bands disappear

In YDSE, when a thin transparent sheet of thickness t and refractive index $\mu$ = 1.5 is placed just in front of the upper slit, the central bright fringe shifts to the nth bright fringe. Then n is [$\mathrm{\lambda }$ $\to$ wavelength of light in the air]

1.  $\frac{t}{2\mathrm{\lambda }}$

2.  $\frac{\mathrm{\lambda }}{2\mathrm{t}}$

3.  $\frac{\mathrm{\lambda }}{\mathrm{t}}$

4.  $\frac{2\mathrm{\lambda }}{\mathrm{t}}$

In YDSE, refer to figure, d >> $\lambda$ and $\mathrm{\theta } = 30°$. The central bright fringe is obtained at distance x above Point C, then x is:

1.  $\frac{\mathrm{D}}{2}$

2.  $\frac{D}{\sqrt{3}}$

3.  2D

4.  Zero

A parallel beam of white light falls on the plane of slits separated by a distance d. The distance above O, at which there will be bright fringe will be:

1.  $\frac{\mathrm{d}}{2}$

2.  $\frac{\mathrm{d}}{3}$

3.  $\frac{\mathrm{d}}{4}$

4.  $\frac{2\mathrm{d}}{3}$

White light is used for double-slit interference, for how many wavelengths, we get maximum at point P shown here on the screen?
                    

1.  1

2.  2

3.  3

4.  7

The figure here shows \(P\) and \(Q\) as two equally intense coherent sources emitting radiations of wavelength \(20~\text{m}\). The separation \(PQ\) is \(5.0~\text{m}\) and the phase of \(P\) is ahead of the phase of \(Q\) by \(90^{\circ}.\)$$\(A, B,\) and \(C\) are three distant points of observation equidistant from the midpoint of \(PQ\). The intensity of radiations at \(A,B,C\) will bear the ratio:

               
1. \(0:1:4\)
2. \(4:1:0\)
3. \(0:1:2\)
4. \(2:1:0\)

In Young's double-slit experiment the intensity of light on screen due to each slit is ${\mathrm{I}}_0$ Interference pattern is observed along a direction parallel to the line $S_1{S}_2$, on-screen S

The minimum, maximum, and the intensity averaged over the entire screen are respectively:

1.  0, 4${\mathrm{l}}_0$, 2${\mathrm{l}}_0$

2.  0, 4${\mathrm{l}}_0$, ${\mathrm{l}}_0$

3.  ${\mathrm{l}}_0$, 2${\mathrm{l}}_0$, 3${\mathrm{l}}_0$/2

4.  0, $2{\mathrm{I}}_0$, ${\mathrm{l}}_0$