In figure assuming the diodes to be ideal:

1. D1 is forward biased and D2 is reverse biased and hence current flows from A to B

2. D1 is reverse biased and D2 is forward biased and hence no current flows from B to A and vice-versa

3. D1 and D2 are both forward biased and hence current flows from A to B

4. D1 and D2 are both reverse biased and hence no current flows from A to B and vice-versa.

Subtopic:  PN junction |
 84%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


The conductivity of a semiconductor increases with an increase in temperature because:

1. number density of free current carriers increases

2. relaxation time increases

3. both number density of carriers and relaxation time increase

4. number density of carriers increases, relaxation time decreases but the effect of decrease in relaxation time is much less than the increase in number density

Subtopic:  Derivation of Ohm's Law |
 81%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


A 220 V AC supply is connected between points A and B (figure). What will be the potential difference V across the capacitor?

 

1. 220 V

2. 110 V

3. 0 V

4. 2202V

Subtopic:  Rectifier |
 55%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


advertisementadvertisement

Write the name of the following gate that the circuit shown in figure.

1. AND gate

2. OR gate

3. NOr gate

4. XOR gate

Subtopic:  PN junction |
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


The reverse bias in a junction diode is changed from 8 V to 13 V, then the value of the current changes from 40 μ A to 60 μ A. The resistance of the junction diode will be: 

1. 2×105 Ω

2. 2.5×105 Ω

3. 3×105 Ω

4. 4×105 Ω

Subtopic:  PN junction |
 91%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


A semiconductor device is connected in a series circuit with a battery and a resistance. A current is found to pass through the circuit. If the polarity of the battery is reversed, the current drops almost to zero. The device may be:

1. a p-type semiconductor

2. an n-type semiconductor

3. a p-n junction

4. an intrinsic semiconductor

Subtopic:  PN junction |
 80%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


advertisementadvertisement

If in a p-n junction diode, a square input signal of 10 V is applied as shown

Then the output signal across RL will be

1. 

2. 

3. 

4. 

Subtopic:  Rectifier |
 74%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


In the given figure, a diode D is connected to an external resistance R=100Ω and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be:


1. 30 mA

2. 40 mA

3. 20 mA

4. 35 mA

Subtopic:  PN junction |
 70%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


The input signal is given to a CE amplifier having a voltage gain of 150 is Vi=2cos15t+II3. The corresponding output signal will be:

1. 30 cos 15t+π3

2. 75 cos 15t+2π3

3. 2 cos 15t+5π3

4. 300 cos 15t+4π3

 79%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.


advertisementadvertisement

If in a p-n junction, a square input signal of 10 V is applied as shown, 

 
then the output across RL will be:
 
 
1. 
 
2. 
 
3. 
 
4. 

 

Subtopic:  Rectifier |
 80%
From NCERT

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.

Hints

To unlock all the explanations of 14 chapters you need to be enrolled in MasterClass Course.